Answer:
-2
Step-by-step explanation:
53 is the mean
70 is the range
there is no mode
51 is the median
Answer:
B.
Step-by-step explanation:
Not another one! ;)
A can be eliminated because the numbers don‘t match. B seems like a possible answer, let’s first check the others out. C and D can be slim instead because the variable, g, should be next to the 1.5 and 2.5. C and D both change the variable location. So, B.
4. ΔBDE ~ ΔBAC; Side-Angle-Side (SAS) Similarity Postulate
5. ∠B ≅ ∠B; Reflexive Property of Equality
Answer:
232°
Step-by-step explanation:
There are a couple of ways to find the desired direction. Perhaps the most straightforward is to add up the coordinates of the travel vectors.
30∠270° +50∠210° = 30(cos(270°), sin(270°)) +50(cos(210°), sin(210°))
= (0, -30) +(-43.301, -25) = (-43.301, -55)
Then the angle from port is ...
arctan(-55/-43.301) ≈ 231.79° . . . . . . . 3rd quadrant angle
The bearing of the ship from port is about 232°.
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<em>Comment on the problem statement</em>
The term "knot" is conventionally used to indicate a measure of speed (nautical mile per hour), not distance. It is derived from the use of a knotted rope to estimate speed. Knots on the rope were typically 47 ft 3 inches apart. As a measure of distance 30 knots is about 1417.5 feet.