A fixed expense<span> is an </span>expense<span> that will be the same total amount regardless of changes in the amount of sales, production, or some other activity. A good example of this is rent or a mortgage.</span>
Answer:
<em>Correct answer:</em>
<em>A. I and II</em>
<em></em>
Step-by-step explanation:
First of all, let us have a look at the steps of finding inverse of a function.
1. Replace y with x and x with y.
2. Solve for y.
3. Replace y with 
Given that:

Now, let us find inverse of each option one by one.
I. y = x, a(x) = x
Replacing y with and x with y:
x = y
x =
=
Hence, I is true.
II. 
Replacing y with and x with y:

=
Hence, II is true.
III. 
Replacing y with and x with y:
Hence, III is not true.
IV. 
Replacing y with and x with y:
Hence, IV is not true.
<em>Correct answer:</em>
<em>A. I and II</em>
<em></em>
Answer:
I believe that it should be Y; Height of an emperor penguin on Antarctica
Answer:
7.5 Quarts
Step-by-step explanation:
D'Naisa mixed the following:
- 1 gallon of orange paint
- 2 quarts of yellow paint
- 3 pints of red paint.
We are to determine in total, the number of quarts of paint that she mixed. this is done by converting each of the volume to quart.
<u>1 gallon of orange paint</u>
- 1 gallon = 4 Quarts
- Orange Paint=4 Quarts
<u>3 pints of red paint.</u>
- 1 pint =0.5 quart
- 3 Pints =3 X 0.5 Quart
- =1.5 Quart of red paint
Therefore,
Total Volume of Paint Mixed in quart= Volume of Orange+Yellow+Red
=4+2+1.5
=7.5 Quarts
9514 1404 393
Answer:
(a, b) = (-2, -1)
Step-by-step explanation:
The transpose of the given matrix is ...
![A^T=\left[\begin{array}{ccc}1&2&a\\2&1&2\\2&-2&b\end{array}\right]](https://tex.z-dn.net/?f=A%5ET%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%26a%5C%5C2%261%262%5C%5C2%26-2%26b%5Cend%7Barray%7D%5Cright%5D)
Then the [3,1] term of the product is ...
![(A\cdot A^T)_{31}=\left[\begin{array}{ccc}a&2&b\end{array}\right]\cdot\left[\begin{array}{ccc}1&2&2\end{array}\right]=a+2b+4](https://tex.z-dn.net/?f=%28A%5Ccdot%20A%5ET%29_%7B31%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%262%26b%5Cend%7Barray%7D%5Cright%5D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%262%5Cend%7Barray%7D%5Cright%5D%3Da%2B2b%2B4)
and the [3,2] term is ...
![(A\cdot A^T)_{32}=\left[\begin{array}{ccc}a&2&b\end{array}\right]\cdot\left[\begin{array}{ccc}2&1&-2\end{array}\right]=2a-2b+2](https://tex.z-dn.net/?f=%28A%5Ccdot%20A%5ET%29_%7B32%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%262%26b%5Cend%7Barray%7D%5Cright%5D%5Ccdot%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%261%26-2%5Cend%7Barray%7D%5Cright%5D%3D2a-2b%2B2)
Both of these terms in the product matrix are 0. We can solve the system of equations by adding these two terms:
(a +2b +4) +(2a -2b +2) = (0) +(0)
3a +6 = 0
a = -2
Substituting for 'a' in term [3,1] gives ...
-2 +2b +4 = 0
b = -1
The ordered pair (a, b) is (-2, -1).