Answer: For problem 8:
sin A/a sinB/b = sinC/c
so sin50/15 = sinB/12
0.766/15 =sinB/12
0.051066 = sin B/12
sin B = 0.6128
B = 37.79 degrees
sum of angles must equal 180 deg therefore C = 180-50-37.79 = 92.21 degrees and .766/15 = sin92.21/c
.051066= 0.99925/c
c = .99925/0.051066 = 19.567
Problems 9 and 10 can also be done with the same method as problem 8.For problem 8:
sin A/a sinB/b = sinC/c
so sin50/15 = sinB/12
0.766/15 =sinB/12
0.051066 = sin B/12
sin B = 0.6128
B = 37.79 degrees
sum of angles must equal 180 deg therefore C = 180-50-37.79 = 92.21 degrees and .766/15 = sin92.21/c
.051066= 0.99925/c
c = .99925/0.051066 = 19.567
Problems 9 and 10 can also be done with the same method as problem 8.
<em>This is not my answer. I shall give credit to the rightful owner of these answers.</em>
Step-by-step explanation:
Which grade are you in? And for which subject?
The area of the path is can be solved using the equation below:
Area path = wide²
First, let us convert 3 feet to inches such as shown below:
3 feet * (12 inches / 1 foot) = 36 inches
Area of the path = 36²
Area of the path = 1296 inches²
Solving for the area of the square bricks
Area of the bricks = (3 inches)²
Area of the brick = 9 inches²
Solving for the number of bricks, we have it:
Total number of bricks = Area of the path/area of the bricks
Total number of bricks = 1296 / 9
Total number of bricks = 144 pieces
The answer is 144 total number of bricks.
20.136 rounded to nearest whole number is 20