ratio of perimeter is the same as ratio of sides so perimeter would be 1:4
since area is in square units you need to square the ratio (1:4)^2 which is 1:16
We'll need to find the 1st and 2nd derivatives of F(x) to answer that question.
F '(x) = -4x^3 - 27x^2 - 48x - 16 You must set this = to 0 and solve for the
roots (which we call "critical values).
F "(x) = -12x^2 - 54x - 48
Now suppose you've found the 3 critical values. We use the 2nd derivative to determine which of these is associated with a max or min of the function F(x).
Just supposing that 4 were a critical value, we ask whether or not we have a max or min of F(x) there:
F "(x) = -12x^2 - 54x - 48 becomes F "(4) = -12(4)^2 - 54(4)
= -192 - 216
Because F "(4) is negative, the graph of the given
function opens down at x=4, and so we have a
relative max there. (Remember that "4" is only
an example, and that you must find all three
critical values and then test each one in F "(x).
Answer:
no
Step-by-step explanation:
2/6 simplifies to 1/3 and 2/4 simplifies to 1/3. 1/2 is greater than 1/3
" the product " means multiply
(2ab + b)(a^2 - b^2) = 2a^3b - 2ab^3 + a^2b - b^3
when multiplied : (2a + b)(2a^3b - 2ab^3 + a^2b - b^3) =
4a^4b - 4a^2b^3 + 2a^3b - 2ab^3 + 2a^3b^2 - 2ab^4 + a^2b^2 - b^4
...result is a polynomial with 8 terms
