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Citrus2011 [14]
3 years ago
9

2 points

Mathematics
1 answer:
Goshia [24]3 years ago
8 0

Answer:

C. I and III

Step-by-step explanation:

The 2 at the upper left means the divisor is x - 2.

The result at the bottom means the quotient is 3x^2 - 4x + 2.

Answer: C. I and III

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What is -3(4r - 8) = -36
sweet [91]

-3(4r - 8) = -36

Mutiply the bracket by -3

(-3)(4r)(-3)(-8)= -12r+24

-12r+24= -36

move +24 to the other side

sign changes from +24 to -24

-12r+24-24= -36-24

-12r= -60

divide by -12

-12r/-12= -60/-12

r= 5

Answer: r= 5

6 0
4 years ago
Read 2 more answers
In your own words, explain to me what is absolute value? Make sure to talk about the definition of it, how you find it, and how
Tom [10]

Answer:

It's a function that associates a real number x with a positive real number using the flowing definition: If the number is not negative (so either positive or 0) the absolute value is x. If x is negative, the absolute value is -x.

This means that to find the absolute value of x you must first determine if x is negative or not, and if it is, multiply it by -1. If it isn't, leave it as it is.

Since the absolute value is a function (of a given number), you can't just plot that number in the number line but the function (so in this case absolute value must be taken first.

The absolute value of x is never negative, so given the absolute value of x we can't determinate if x was positive or negative (if x =/ 0) before the absolute value was taken.

4 0
3 years ago
Question 8(Multiple Choice Worth 1 points)
Marianna [84]

Q8: a. 270

Q9: b. 78.5%

Q10: c. 36

Q11: d. 1/5

Q12: a. 0.4

4 0
4 years ago
What is the answer to 6(-⅔) =
horsena [70]

Answer:

-4

Step-by-step explanation:

  1. 6 × -\frac{2}{3} = -4

I hope this helps!

5 0
3 years ago
Read 2 more answers
Lines
SashulF [63]

Answer:

5 cm

Step-by-step explanation:

If AB is tangent to the circle k(O), then radius OB is perpendicular to segment AB.

If BC is tangent to the circle k(O), then radius OC is perpendicular to segment AC.

Consider two right triangles ABO and ACO. In these triangles:

  • AO is common hypotenuse;
  • ∠OBA=∠OCA=90°, because AB⊥OB, AC⊥OC;
  • OB=OC as radii of the circle k(O).

By HL theorem, triangles ABO and ACO are congruent. Then

  • ∠OAB=∠OAC=30°;
  • AC=AB=5 cm.

Hence, ∠BAC=∠OAB+∠OAC=30°+30°=60°.

Consider triangle ABC, this triangle is isosceles triangle. In isosceles triangles angles adjacent to the base are congruent, thus

∠CBA=∠BCA=1/2(180°-60°)=60°.

Therefore, triangle ABC is an equilateral triangle, so BC=AB=AC=5 cm.

5 0
3 years ago
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