2cos^2 x + 3sin x = 0
2(1 - sin^2 x) + 3sin x = 0
2 - 2sin^2 x + 3sin x = 0
2sin^2 x - 3sin x - 2 = 0
Let sin x = m, then
2m^2 - 3m - 2 = 0
2m^2 + m - 4m - 2 = 0
m(2m + 1) - 2(2m + 1) = 0
(m - 2)(2m + 1) = 0
m = 2 or m = -1/2
Now, sin x = -1/2
Therefore, x = 1/6(12nπ - π) and 1/6(12nπ + 7π)
Y= (2x-20)/ 5 then you replace y so with a simple calculation u get x than u replace x with it value to get y as simple as that
Answer:
666 + 66 + 6 + 6 + 6 = 750
i think that is what u meant and if not plz tell me
Answer:q=9
Step-by-step explanation: