What’s the 2 answers?

Mathematics

1 answer:

emmainna [20.7K]3 years ago

6 0

Answer:

X<10 and x<4

Step-by-step explanation:

The absolute value bars around the x-7 means that the problem is less than 3 and less than negative 3, so you must solve for both to find all correct answers

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sveticcg [70]

$y=\sqrt{3x+5}\\\\The\ domain:\\\\3x+5\geq0\ \ \ |-5\\\\3x\geq-5\ \ \ |:3\\\\x\geq-\dfrac{5}{3}\to x\in\left[-\dfrac{5}{3};\ \infty\right)$

6 0

3 years ago

Read 2 more answers

Please answer and explain the link below

Leviafan [203]

Answer:

See explanation.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation

Calculus

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \left \{ {{\sqrt{x + 1}, \ x < 3} \atop {5 - x, \ x \geq 3}} \right.$

Step 2: Find Right Limit

Substitute in variables [Right-Side Limit]: $\displaystyle \lim_{x \to 3^+} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 3^+} 5 - x = 5 - 3$
Subtract: $\displaystyle \lim_{x \to 3^+} 5 - x = 2$

∴ the right-side limit equals 2.

Step 3: Find Left Limit

Substitute in variables [Left-Side Limit]: $\displaystyle \lim_{x \to 3^-} \sqrt{x + 1}$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 3^-} \sqrt{x + 1} = \sqrt{3 + 1}$
[√Radical] Add: $\displaystyle \lim_{x \to 3^-} \sqrt{x + 1} = \sqrt{4}$
[√Radical] Evaluate: $\displaystyle \lim_{x \to 3^-} \sqrt{x + 1} = 2$