All categories

3 years ago

An ant is 20 x 10^-3 m long. If you put 10 million ants in a line, how long is the line?

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

One ant = .02

10,000,000 x 0.2 =

200,000m

Hope that helps!

yanalaym [24]3 years ago

4 0

Answer:

A. 200m

B. 2,000m

C. 20,000m the answer

D. 200,000m

You might be interested in

What does a zero slope line look like

nikdorinn [45]

It's a horizontal line

4 0

3 years ago

Simplify expression x8y-26/x14y-5 × x-39y-21

koban [17]

The simplified form of the expression is $x^{-45} y^{-42}$

<h3>Simplifying an expression</h3>

From the question, we are to simplify the given expression

The given expression is

$\frac{x^{8}y^{-26} }{x^{14}y^{-5} } \times x^{-39} y^{-21}$

The expression can be simplified as shown below

$\frac{x^{8}y^{-26} }{x^{14}y^{-5} } \times x^{-39} y^{-21}$

$\frac{x^{8} \times x^{-39} \times y^{-26} \times y^{-21} }{x^{14} \times y^{-5} }$

$\frac{x^{8+-39} \times y^{-26+-21} }{x^{14} \times y^{-5} }$

$\frac{x^{8-39} \times y^{-26-21} }{x^{14} \times y^{-5} }$

$\frac{x^{-31} \times y^{-47} }{x^{14} \times y^{-5} }$

Then,

$\frac{x^{-31} }{x^{14} } \times \frac{ y^{-47} }{ y^{-5} }$

$x^{-31-14} \times y^{-47--5}$

$x^{-31-14} \times y^{-47+5}$

$x^{-45} \times y^{-42}$

$x^{-45} y^{-42}$

Hence, the simplified form of the expression is $x^{-45} y^{-42}$

Learn more on Simplifying an expression here: brainly.com/question/2320607

#SPJ1

3 0

2 years ago

Please help!!!!!!!!!!

BabaBlast [244]

Answer:

Step-by-step explanation:

ez claps pie

7 0

3 years ago

What is the following sum?

marta [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Here's another geometry thing I suck at...

solniwko [45]

A = 133; b = 31; c = 82; d = 64.
Opposite angles in an inscribed quadrilateral are supplementary; this means that d + 116 = 180. Subtracting 116 from both sides, we have d = 64.

By the same theorem, c + 98 = 180; subtracting 98 from both sides, we have c = 82.

Inscribed angles are equal to 1/2 the measure of the intercepted arc. Using this, we have

116 = 1/2(a+99)

Multiplying both sides by 2, we have
232 = a+99

Subtract 99 from both sides:
232 - 99 = a + 99 - 99
133 = a

We also have that
82 = 1/2(133+b)

Multiplying both sides by 2, we have:
164 = 133 + b

Subtract 133 from both sides:
164 - 133 = 133 + b - 133
31 = b

6 0

4 years ago