Answer:
Answer:
Option (C)
Step-by-step explanation:
Given function is F(x) = x³+ 4x² + x - 6
Possible rational zeros of this function = \frac{\pm1,\pm2,\pm3,\pm6}{\pm1}
±1
±1,±2,±3,±6
[Possible rational zeros of a function f(x) = ax³+ bx² + cx + d,
= \frac{\text{factors of d}}{\text{factors of a}}
factors of a
factors of d
Let the possible zero of this function is 2.
Now do the synthetic division,
2| 1 4 1 -6
↓ 2 12 26
1 6 13 20
Here all the numbers at the bottom are positive by dividing with a positive number 2, therefore, 2 is the upper bound.
There will be no rational zero (Positive) above 2.
Therefore, Option (C) will be the answer.
