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andre [41]
3 years ago
13

Which ordered pairs are solutions to the system? Check all of the boxes that apply.

Mathematics
2 answers:
77julia77 [94]3 years ago
7 0

Answer:

the answer is the 3rd & 5th one for anyone doing this question ; )

Step-by-step explanation:

I just did this question

It's right i just checked

lianna [129]3 years ago
6 0

Answer:

C & E

Step-by-step explanation:

Just took it. Edg 2020. Hope this helps :)

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Divide x^3+2 by x+1<br> long division<br> ppleeease! :)
anzhelika [568]

     Long division:   (x³ + 2)  ÷  (x + 1)


                                        <u>    </u><u>x² –  x  +  1   </u>
      x³ + 0x² + 0x + 2      |    x  +  1
   <u>– x³ –   x²</u>    ⋮       ⋮
          –   x² + 0x     ⋮
          <u>+   x² +   x</u><span>     ⋮</span>
                    +  x + 2
<span>                   </span> <u>–  x – 1</u>
                            + 1


         Quotient:   Q(x) = x² – x – 1;
  
     Remainder:   R(x) = + 1.


I hope this helps. =)

3 0
3 years ago
Seventy-five 6th-grade students chose to watch a movie on the last day of school.
EleoNora [17]

Answer:

c.300

Step-by-step explanation:

25%-----75 studens

100%-----x students

x=100×75/25= 300

5 0
3 years ago
3 ⅕ -⅔ divided by 2 ⅘
spin [16.1K]

Answer:

160/196

Step-by-step explanation:

it would be easier if you converted all fractions to improper fractions

so 3 1/5 would equal 16/5 and 2 4/5 would equal to 14/5

\frac{14}{5} - \frac{2}{3} : to solve this you would need the same common denomenator,

to do this you can multiply 5 and 3 by something to make the lowest common denominator, which would be 15

thus

multiplying first fraction by 3 and the second by 5

42/15 - 10/15 = 32/15

now 32/15 divided by 14/5

the rule for dividing fractions, is flipping the fraction which you will be using to divide, and then multiplying it to the first fraction:

\frac{32}{14} multiplied by \frac{5}{14}

thus, answer is 160/196

8 0
3 years ago
The answers are 2x1/3 , 3x1/3, 5x1/3or 4x1/3
Oxana [17]

Answer:

what is the question? Please ask a question.

6 0
3 years ago
If f(x)=x^5-1 g(x)=5x^2 and h(x)=2x which expression is equivalent to [g*f*h](9)
vagabundo [1.1K]
F(x) = x^5 - 1; g(x) = 5x^2; h(x) = 2x

Answer:
\underbrace{5(\underbrace{(\underbrace{2\cdot9}_{h(9)})^5-1}_{f(g(9))})^2}_{g(f(h(9)))}    \boxed{C.}
6 0
3 years ago
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