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dolphi86 [110]
2 years ago
13

Given the function F (x) = x2 -2x -5 determine the average rate of change of the function over the interval -5 < x <6.

Mathematics
1 answer:
KengaRu [80]2 years ago
4 0

Answer:

1

Step-by-step explanation:

Here f(x) = x^2 - 2x - 5, which at x - -5 is 25 +10 - 5 = 30 and at x = 6 is 19.

The average value of a function f(x) over an interval [a, b] is

                  f(b) - f(a)

ave. val. = ---------------

                     b - a

which in this particular case is

                     19 - 30

ave. val. = ----------------- = -11/11 = 1

                     6 - (-5)

The average value of this function f(x) = x^2 - 2x - 5 on [-5, 6] is 1.

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The cost of a large cake at a bakery is $21.00. The cost of a small cake is
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Answer:

The Subtotal cost of all the cakes before tax and delivery

Step-by-step explanation:

(21x+8.25y)

21 is the price of 1 large cake and X is the number of cakes they want to purchase not counting tax and delivery fee.

8.25 is the price of 1 small cake and Y is the number of cakes they want to purchase not counting tax and delivery fee.

8 0
2 years ago
First person to answer what 4585 times 5645 CORRECT first gets brainiest
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Step-by-step explanation:

Simply do 4585*5645 in a calculator.

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3 0
3 years ago
Read 2 more answers
Need help please thank you
Nookie1986 [14]

Answer:

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Step-by-step explanation:

7 0
2 years ago
What is the solution to this equation?<br> x-8=15<br><br> A)x=13<br> B)x=17<br> C)x=7<br> D) x=23
Blababa [14]

Hi there! :)

<u><em>Answer:</em></u>

<u><em>x=23</em></u>

<u><em>*The answer must have a positive sign.*</em></u>

Step-by-step explanation:

This lesson it's about addition property of equality.

First, you add by 8 from both sides of an equation.

x-8+8=15+8

And then, you add by the numbers. Simplify and solve.

15+8=23

Final answer: → x=23

Hope this helps!

Thanks!

-Charlie

Have a great day!

:)

:D

3 0
3 years ago
Luis has a $10 and three $5 bills. He spends $12.75 on entrance fee to an amusement park and $8.50 on snacks. How much does he h
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