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2 years ago

How much energy is absorbed by 250.0 g of water when its temperature rises

Mathematics

1 answer:

kari74 [83]2 years ago

7 0

Answer:

(4.18 J/g°C) x (100.0 mL x 1.000 g/mL) x (37 - 4.0)°C = 13794 J = 13 kJ

(455 J) / (25.0 g) / (155 - 25)°C = 0.140 J/g°C

(4.184 J/g°C) x (20.0 g) x (303.0 - 283.0)°C = 1674 J

(0.129 J/g °C) x (85.0 g) x (200.0 - 10.0)°C = 2083 J

Step-by-step explanation:

I think this is the right answer, I am very, very sorry if I'm wrong

Have a Great Day or Night! :)

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