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2 years ago

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How much energy is absorbed by 250.0 g of water when its temperature rises

1 answer:

kari74 [83]2 years ago

7 0

Answer:

.

(4.18 J/g°C) x (100.0 mL x 1.000 g/mL) x (37 - 4.0)°C = 13794 J = 13 kJ

2.

(455 J) / (25.0 g) / (155 - 25)°C = 0.140 J/g°C

3.

(4.184 J/g°C) x (20.0 g) x (303.0 - 283.0)°C = 1674 J

5.

(0.129 J/g °C) x (85.0 g) x (200.0 - 10.0)°C = 2083 J

Step-by-step explanation:

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Canadians who visit the United States often buy liquor and cigarettes, which are much cheaper in the United States. However, the

fenix001 [56]

Answer:

(a): Marginal pmf of x

$P(0) = 0.72$

$P(1) = 0.28$

(b): Marginal pmf of y

$P(0) = 0.81$

$P(1) = 0.19$

(c): Mean and Variance of x

$E(x) = 0.28$

$Var(x) = 0.2016$

(d): Mean and Variance of y

$E(y) = 0.19$

$Var(y) = 0.1539$

(e): The covariance and the coefficient of correlation

$Cov(x,y) = 0.0468$

$r \approx 0.2657$

Step-by-step explanation:

Given

<em>x = bottles</em>

<em>y = carton</em>

<em>See attachment for complete question</em>

<em />

Solving (a): Marginal pmf of x

This is calculated as:

$P(x) = \sum\limits^{}_y\ P(x,y)$

So:

$P(0) = P(0,0) + P(0,1)$

$P(0) = 0.63 + 0.09$

$P(0) = 0.72$

$P(1) = P(1,0) + P(1,1)$

$P(1) = 0.18 + 0.10$

$P(1) = 0.28$

Solving (b): Marginal pmf of y

This is calculated as:

$P(y) = \sum\limits^{}_x\ P(x,y)$

So:

$P(0) = P(0,0) + P(1,0)$

$P(0) = 0.63 + 0.18$

$P(0) = 0.81$

$P(1) = P(0,1) + P(1,1)$

$P(1) = 0.09 + 0.10$

$P(1) = 0.19$

Solving (c): Mean and Variance of x

Mean is calculated as:

$E(x) = \sum( x * P(x))$

So, we have:

$E(x) = 0 * P(0) + 1 * P(1)$

$E(x) = 0 * 0.72 + 1 * 0.28$

$E(x) = 0 + 0.28$

$E(x) = 0.28$

Variance is calculated as:

$Var(x) = E(x^2) - (E(x))^2$

Calculate $E(x^2)$

$E(x^2) = \sum( x^2 * P(x))$

$E(x^2) = 0^2 * 0.72 + 1^2 * 0.28$

$E(x^2) = 0 + 0.28$

$E(x^2) = 0.28$

So:

$Var(x) = E(x^2) - (E(x))^2$

$Var(x) = 0.28 - 0.28^2$

$Var(x) = 0.28 - 0.0784$

$Var(x) = 0.2016$

Solving (d): Mean and Variance of y

Mean is calculated as:

$E(y) = \sum(y * P(y))$

So, we have:

$E(y) = 0 * P(0) + 1 * P(1)$

$E(y) = 0 * 0.81 + 1 * 0.19$

$E(y) = 0+0.19$

$E(y) = 0.19$

Variance is calculated as:

$Var(y) = E(y^2) - (E(y))^2$

Calculate $E(y^2)$

$E(y^2) = \sum(y^2 * P(y))$

$E(y^2) = 0^2 * 0.81 + 1^2 * 0.19$

$E(y^2) = 0 + 0.19$

$E(y^2) = 0.19$

So:

$Var(y) = E(y^2) - (E(y))^2$

$Var(y) = 0.19 - 0.19^2$

$Var(y) = 0.19 - 0.0361$

$Var(y) = 0.1539$

Solving (e): The covariance and the coefficient of correlation

Covariance is calculated as:

$COV(x,y) = E(xy) - E(x) * E(y)$

Calculate E(xy)

$E(xy) = \sum (xy * P(xy))$

This gives:

$E(xy) = x_0y_0 * P(0,0) + x_1y_0 * P(1,0) +x_0y_1 * P(0,1) + x_1y_1 * P(1,1)$

$E(xy) = 0*0 * 0.63 + 1*0 * 0.18 +0*1 * 0.09 + 1*1 * 0.1$

$E(xy) = 0+0+0 + 0.1$

$E(xy) = 0.1$

So:

$COV(x,y) = E(xy) - E(x) * E(y)$

$Cov(x,y) = 0.1 - 0.28 * 0.19$

$Cov(x,y) = 0.1 - 0.0532$

$Cov(x,y) = 0.0468$

The coefficient of correlation is then calculated as:

$r = \frac{Cov(x,y)}{\sqrt{Var(x) * Var(y)}}$

$r = \frac{0.0468}{\sqrt{0.2016 * 0.1539}}$

$r = \frac{0.0468}{\sqrt{0.03102624}}$

$r = \frac{0.0468}{0.17614266944}$

$r = 0.26569371378$

$r \approx 0.2657$ --- approximated

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2 years ago

Classify each polynomial by degree and number of terms. 1. Quartic monomial v 5x? - 7x + 9 2. Cubic binomial 2x3 + 3 < 3. Qua

ElenaW [278]

The degree of a polynomial is categorized by its highest power of its leading variable.

<h3>Degree and number of terms of a polynomial</h3>

Given the following polynomial functions, we are to classify them based on their degrees and the number of terms

For the polynomial function 5x^4 - 7x + 9

The degree is 4 being quartic and there are three terms in the expression

For the polynomial 2x3 + 3 < 3, the degree is 3 (cubic) with three terms in the expression.

For a Quintic quadnomial, the degree of the polynomial is 5.

Learn more on polynomials here: brainly.com/question/4142886

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2 years ago

Please show work for both problems

sukhopar [10]

(1) The value of x is 25

(2) The measure of ∠CBD is 60°

Explanation:

(1) The given two angles are vertical angles. Since, vertical angles are equal, we can add the two angles to determine the value of x.

Thus, we have,

$5x+15=6x-10$

Subtracting 5x from both sides, we have

$15=x-10$

Adding 10 to both sides , we have,

$25=x$

Thus, the value of x is 25.

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Since, these two angles are supplementary angles and supplementary angles add upto 90°

Thus, we have,

$2x+14+x+7=90$

Simplifying, we get,

$3x+21=90$

$3x=69$

$x=23$

Thus, substituting the value of x in ∠CBD = (2x+14)° to determine its value.

$2x+14=2(23)+14=46+14=60$

Thus, the measure of ∠CBD is 60°

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Joshua went kayaking. It cost him $ 15 to rent the kayak. It also cost $ 6 for each hour spent on the lake kayaking. Joshua spen

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Step-by-step explanation:

The total bill will be the sum of the rent and the cost for the total time spent.

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