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Masteriza [31]
3 years ago
13

If a student correctly graphs a system of equations, which statement is true?

Mathematics
1 answer:
eimsori [14]3 years ago
5 0

If a student <em>correctly</em> graphs a system of equations, which statement is true?

Answer: the THIRD ANSWER CHOICE is the true statement.

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Write the whole number as an equivalent fraction with the given denominator.<br><br> 3= 4
ANTONII [103]

Answer: 12/4

Step-by-step explanation: whole number = 3. given denominator = 4. 4/4 = 1. 1 times 3 = 3. 4 plus 4 plus 4 = 12. therefore answer is 12/4

7 0
2 years ago
89.891 to the nearest ten thousands place
Orlov [11]
89.890 Is what I would think it would be. Hope it helped.

7 0
3 years ago
7
jeyben [28]

Answer:

x = -2

Step-by-step explanation:

Given the point, (-2, 9) and the linear equation of a <u>horizontal line</u>, y = 6:

The linear equation of a horizontal line with a slope of zero (<em>m</em> = 0) is y = <em>b, </em>for which the y-intercept is (0, <em>b</em>). <u>Perpendicular lines</u> comprise of the intersection of two lines forming 90° angles.  

Since we are given the equation of a horizontal line, then we can assume that <em>the line that intersects a horizontal line must be a </em><u><em>vertical line</em></u> in order to form perpendicular lines.

The linear equation of a <u>vertical line</u> with an undefined slope is <em>x</em> = <em>a</em>, for which the x-intercept is (<em>a</em>, 0). Vertical lines have an <u>undefined slope </u>because these lines do not have any horizontal change. Thus, when you try to solve for its slope, the denominator will have a difference of 0, making the mathematical operation undefined.

We can use the <u>x-coordinate</u> of the given point, (-2, 9), to formulate an equation for a vertical line: x = -2.

Therefore, the equation of the line that goes through y = 6 is x = -2.

Attached is a screenshot of the graph of both equations, y = 6 and x = -2, showing that their intersection form 90° angles, making them perpendicular lines.      

8 0
3 years ago
Customers per day: 98, 87, 93, 82, 101, 99, 97, 97, 91<br> Find the mean to the nearest tenth:
notsponge [240]
<h2>Mean = 93.3 (to nearest tenth).</h2><h2 /><h2>Mean = 93.3 (to nearest tenth).Median = 97.</h2><h2 /><h2>Mean = 93.3 (to nearest tenth).Median = 97.Mode = 97.</h2><h2 /><h2>Mean = 93.3 (to nearest tenth).Median = 97.Mode = 97.Step-by-step explanation:</h2><h2 /><h2>Mean = 93.3 (to nearest tenth).Median = 97.Mode = 97.Step-by-step explanation:Arrange the data in ascending order:</h2><h2 /><h2>Mean = 93.3 (to nearest tenth).Median = 97.Mode = 97.Step-by-step explanation:Arrange the data in ascending order:79 82 87 91 93 97 97 98 99 101 102</h2><h2 /><h2>Mean = 93.3 (to nearest tenth).Median = 97.Mode = 97.Step-by-step explanation:Arrange the data in ascending order:79 82 87 91 93 97 97 98 99 101 102There are 11 numbers.</h2><h2 /><h2>Mean = 93.3 (to nearest tenth).Median = 97.Mode = 97.Step-by-step explanation:Arrange the data in ascending order:79 82 87 91 93 97 97 98 99 101 102There are 11 numbers.The Median is the center value (= the 6th</h2><h2>Mean = 93.3 (to nearest tenth).Median = 97.Mode = 97.Step-by-step explanation:Arrange the data in ascending order:79 82 87 91 93 97 97 98 99 101 102There are 11 numbers.The Median is the center value (= the 6thnumber) = 97.</h2><h2 /><h2>Mean = 93.3 (to nearest tenth).Median = 97.Mode = 97.Step-by-step explanation:Arrange the data in ascending order:79 82 87 91 93 97 97 98 99 101 102There are 11 numbers.The Median is the center value (= the 6thnumber) = 97.The mode = highest occurring value = 97.</h2><h2 /><h2>Mean = 93.3 (to nearest tenth).Median = 97.Mode = 97.Step-by-step explanation:Arrange the data in ascending order:79 82 87 91 93 97 97 98 99 101 102There are 11 numbers.The Median is the center value (= the 6thnumber) = 97.The mode = highest occurring value = 97.The mean = sum / 11 = 93.3.</h2>

7 0
3 years ago
Read 2 more answers
Help with this immediately​
charle [14.2K]

x= 2

Step-by-step explanation:

The answer for what does x= is,

x = 2

6 0
4 years ago
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