Answer:
x=0
y=6
Step-by-step explanation:
Two equations with two unknowns can be solved. Use the three steps given below.
In general you can save time if you use the simplest expression for step 1. You can choose either expression to start with x =.. or you can rewrite it, so it starts with y =...
FOLLOW THESE STEPS:
1. Rewrite the first expression so it starts with y =...
2. Then use that expression and substitute it in the other expression, to find the value for x.
3. Use that value found in step 2. and substitute it in the rewritten expssion you created in step 1. Solve this last expression and you'll get the value for y.
Step 1.
-6y + 11x = -36
-6y = -11x -36
multiply left and right of the = sign by -1
6y = 11x + 36
divide left and right of the = sign by 6
y = 11x/6 + 36/6
y = 11/6x + 6
Step 2.
-4 * ( y ) + 7x = -24
-4 * ( 11/6x + 6 ) + 7x = -24
( -44/6x - 24 ) + 7x = -24
-44/6x + 7x = -24 + 24
You can see immediately that ...x = 0
Just for fun of it ....
-44/6x + 42/6x = 24 - 24
(-44+42)/6x = 0
-2/6x = 0
-1/3x = 0
multiply left and right of the = sign by -3
3/3x = 0 * -3
x = 0
Step 3.
y = 11/6( x ) + 6. and substitute x = 0 gives:
y = 11/6( 0) + 6
y = 0 + 6
y = 6
Answer:
A
Step-by-step explanation:
Given (x + h) is a factor of f(x) then f(- h) = 0
Given
p(x) = x³ - 4x² + ax + 20 , with (x + 1) as a factor then
p(- 1) = (- 1)³ - 4(- 1)² - a + 20 = 0 , that is
- 1 - 4 - a + 20 = 0
15 - a = 0 ( subtract 15 from both sides )
- a = - 15 ( multiply both sides by - 1 )
a = 15 , thus
p(x) = x³ - 4x² + 15x + 20
If p(x) is divided by (x + h) then p(- h) is the remainder, so
p(- 2) = (- 2)³ - 4(- 2)² + 15(- 2) + 20 , that is
- 8 - 16 - 30 + 20 = - 34 → A
24 because 12 times 2 is equal to 24
The given equation is:
We need to find which set of parametric equations, result in the equation given above. The correct answer is option A.
From first equation, we can write t =x/5. Using this value in second equation, we get:
Thus the set of equations in option A result in the given relation.
So, the answer to this question is option A
