To prove a similarity of a triangle, we use angles or sides.
In this case we use angles to prove
∠ACB = ∠AED (Corresponding ∠s)
∠AED = ∠FDE (Alternate ∠s)
∠ABC = ∠ADE (Corresponding ∠s)
∠ADE = ∠FED (Alternate ∠s)
∠BAC = ∠EFD (sum of ∠s in a triangle)
Now we know the similarity in the triangles.
But it is necessary to write the similar triangle according to how the question ask.
The question asks " ∆ABC is similar to ∆____. " So we find ∠ABC in the prove.
∠ABC corressponds to ∠FED as stated above.
∴ ∆ABC is similar to ∆FED
Similarly, if the question asks " ∆ACB is similar to ∆____. "
We answer as ∆ACB is similar to ∆FDE.
Answer is ∆ABC is similar to ∆FED.
Assuming that the given shape is a cuboid,
volume=l×w×h
v=s³ (since cuboids have same length, they have same side length)
62=s³
∛62=s
s=3.957 ≈ 4 units
Hope I helped :)
Answer:
the answer is c.768
Step-by-step explanation:
Answer:
0.525
Step-by-step explanation:
\frac{x}{3.50}=\frac{15}{100}
