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Novay_Z [31]
2 years ago
15

After spending 2/5 of her pocket money,Joyce realised she has spent $18.00. find her pocket money.​

Mathematics
1 answer:
Solnce55 [7]2 years ago
3 0

Answer:

1235674895

Step-by-step explanation8

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What is the slope and y intercept of -2x +3y=-9
attashe74 [19]

Answer:

m = 2/3

b = -3

Step-by-step explanation:

Rearrange the equation to slope-intercept form (y = mx + b).

x and y are points on the graph.

m is the slope.

b is the y-intercept.

Isolate "y". This means separating it from the other numbers.

-2x +3y = -9

-2x + 2x +3y = -9 + 2x    Add 2x to both sides

3y = 2x - 9

3y/3 = 2x/3 - 9/3      Divide both sides by 3

y = 2x/3 - 9/3      Simplify

y = (2/3)x - 3

Think about which numbers and "m" and "b" now that the equation is in y = mx + b. Include the plus and minus signs.

m = 2/3

b = -3

8 0
2 years ago
1 2 3 4 5 6 7 8 9 10
Maslowich

The graph that represents viable values for y = 2x is Option A.

<h3>What is a Straight Line Function ?</h3>

A straight line function is given by y = mx +c , where m is the slope and c is the y intercept.

The given equation is y = 2x

here m  = 2

x is the number of pounds of rice scooped and purchased from a bulk bin

y is the total cost of the rice

as both the data cannot be negative , Option C , D is out of choice

The Option 1 represents a straight line and it starts at the origin which is satisfied by y = 2x as y = 0 , at x = 0

ends at  point (2.5, 5) giving a slope of m =2 ,

Therefore , The graph that represents viable values for y = 2x is Option A.

To know more about Straight Line equation

brainly.com/question/959487

#SPJ1

6 0
2 years ago
What is the range of function y=√(-2cos^2x+3cosx-1)
Ugo [173]
Hello Friend,here is the solution for your question


<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
 i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here  in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2)   is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>


And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0    [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>

<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
   =√[1/8-3(0)]        [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
     =√1/8
      =1/(2√2)

<span>this is the maximum value now to find the minimum value </span>

<span>since this is function of root so the value of y will always be ≥0 </span>

<span>hence the minimum value of the function y is 0 </span>


<span>Therefore, the range of function </span>y is [0,1/(2√2)]


__Well,I have explained explained each and every step,do tell me if you don't understand any step._

8 0
3 years ago
Which points on the graph represent values that could be in the table? A B C D
Dafna11 [192]

Answer:

uhhh

Step-by-step explanation:

uh I don't see the graph

4 0
3 years ago
Read 2 more answers
Find the equation of the line<br> In the form y=mx+b
Aleonysh [2.5K]

Answer:

y = -1/3x + 5

Step-by-step explanation:

-1/3 is the slope because the line goes down 1 unit and right 3 units.

The y-intercept is 5 because that is where the line crosses the y-axis.

8 0
3 years ago
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