Answer: okay so first solve for x which is going to be x=10
Step-by-step explanation:
Answer: 0
Step-by-step explanation:
h ( t ) = − 2 t ^2 + 10 t
h = height of ball above the ground
t = time, seconds after ball was kicked
Height of ball at the time it is kicked?
At the time ball is kicked, time (t) = 0
Therefore,
h ( t ) = − 2 t ^2 + 10 t
h( 0) = - 2(0)^2 + 10(0)
h = 0 + 0
h = 0
The ball was the on the grounf at the time it was kicked.
Answer:
length of 1 side of A, using the Pyth. Thm. and the dimensions of the other two squares: (side of A)^2 = (10 in)^2 + (24 in)^2. Then:
(side of A)^2 = 100+ 576 in^2 = 676 in^2.
Here I have not bothered to solve for the length of the side of A, since we want the area of square A. But if you do want the side length, find it: sqrt(676) = 26 in. Then the area of A is (26 in)^2 = 676 in^2.
Then the area of square A is (26 in)^2 =
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Step-by-step explanation:
Answer:
Step-by-step explanation:
Hypotenuse^2=3^2+8^2
Hypotenuse^2=9+64=73
Hypotenuse =square root of 73
Hypptenuse =8.54
Answer:
it's 0.01 (approx.)
Step-by-step explanation:
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