A^2 + b^2 = c^2
the sides are 11, 13, and 25
11^2+13^2=290
25^2 = 625
11^2+13^2<25^2
So, this is an obtuse triangle
Answer
C) 160 in^2
Step by step explanation
First, let's find the area of the rectangle.
Area of a rectangle = length x width
The area of the rectangle = 20 * 10
= 200 in^2
Now let's find the area of the triangle that is removed.
Area of a triangle = 1/2 base * height.
Here base = 10 and height = 8. Plug in these values into the formula, we get
Area of the triangle = 1/2 * 10*8
= 5* 8
The area of the triangle = 40 in^2
The area of the remaining figure = Area of the rectangle - area of the triangle
= 200 - 40
= 160 in^2
The answer is "160 in^2"
Thank you.
Answer:
The length of the flag is 730 ft and the width is 310 ft
Step-by-step explanation:
<u><em>The correct question is</em></u>
The perimeter of the flag is 2080 ft what is the flags width and length <u>if</u> the length is 420 ft greater than the width
Let
L ----> the length of the flag
W ---> the width of the flag
we know that
The perimeter of the flag (rectangle) is equal to
we have
so
----> equation A
---> equation B
Solve the system by substitution
substitute equation B in equation A
solve for W
<em>Find the value of L</em>
----> 
therefore
The length of the flag is 730 ft and the width is 310 ft
Answer:
TUP and PUQ
Step-by-step explanation:
Adjacent angles share a common vertex and common side, but don't overlap.
