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Helen [10]
2 years ago
12

PLEASE HELPPP ASAPP!! Combine and simplify the following radical expression.

Mathematics
1 answer:
Greeley [361]2 years ago
7 0

After demonstrating the procedure by algebraic means, the expression (2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} ) <em>is equivalent to</em> 6\cdot \sqrt[3]{24}.

In this question we proceed to <em>simplify</em> (2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} ) by <em>algebraic</em> means into a <em>single</em> <em>radical</em> expression when possible, whose procedure is shown below and explained by appropriate definitions and theorems:

  1. (2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} )  Given.
  2. (2\cdot 3) \cdot (\sqrt[3]{12} \cdot \sqrt[3]{2}  ) Commutative property/ Associative property.
  3. 6\cdot \sqrt[3]{24} Definition of cubic root/\sqrt[n]{a} = \sqrt[n]{b}/Result

After demonstrating the procedure by algebraic means, the expression (2\sqrt[3]{12} )\cdot (3\sqrt[3]{2} ) <em>is equivalent to</em> 6\cdot \sqrt[3]{24}.

To learn more on radical expressions, we kindly invite to check this verified question: brainly.com/question/1810591

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Solve the following system:<br> y=1<br> y=-6x-5
Mandarinka [93]

Answer:

x = -1

y = 1

Step-by-step explanation:

<u><em>Since it gives you "y", plug in the number given into the equation:</em></u>

y = -6x - 5

1 = -6x - 5

<u><em>Then, add 5 to both sides:</em></u>

1 = -6x - 5

+5       + 5

________

6 = -6x

<em><u>Divide both sides by -6:</u></em>

6 = -6x

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So now you have, x = -1 and y = 1

4 0
3 years ago
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Consider the function represented by the equation y-6x-9=0. Which answer shows the equation written in function notation with x
Marta_Voda [28]

Answer:

A. f(x) = 6x + 9

Step-by-step explanation:

The given equation is:

y - 6x - 9 = 0

We have to write this equation in function notation with x as the independent variable. This means that y will be replaced by f(x) and all other terms will be carried to the other side of the equation to get the desired function notation.

y - 6x - 9 = 0

y = 6x + 9

f(x) = 6x + 9

Therefore, option A gives the correct answer.

5 0
2 years ago
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Use quadratic formula to find both solutions to the quadratic equation given below . 3x^2-5x-1=0
Rudiy27

Answer:

x1=\frac{5+\sqrt{37}} {6}

x2=\frac{5-\sqrt{37}} {6}

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^{2} -5x-1=0  

so

a=3\\b=-5\\c=-1

substitute in the formula

x=\frac{5(+/-)\sqrt{(-5)^{2}-4(3)(-1)}} {2(3)}

x=\frac{5(+/-)\sqrt{37}} {6}

x1=\frac{5+\sqrt{37}} {6}

x2=\frac{5-\sqrt{37}} {6}

8 0
3 years ago
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