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3 years ago

I need help please no links i just need the answer please i can’t fail

Mathematics

1 answer:

Genrish500 [490]3 years ago

5 0

Answer:

Step-by-step explanation:

just trust me

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A boy is standing next to a radio. As he moves away from the radio, which would MOST LIKELY occur?

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Read 2 more answers

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

3 years ago

Can someone help me solve this step by step?

patriot [66]

Answer:

41 and 77

Step-by-step explanation:

x: his age the first time he went to space

y: his age the second time he went to space

the second time he went to space he was 5 years younger than twice the age when he went his first time, then:

y = 2x - 5

the sum of both ages is 118, then:

x + y = 118

If you replace y = 2x - 5 in x + y =118:

x + 2x - 5 = 118

3x = 123

x = 41

replacing x:

41 + y = 118

y = 118 - 41

y = 77

so when he was 77, he was 5 years younger than twice 41 ( 41*2 = 82 => 82 - 5 =77)

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3 years ago

What is this shape called?

shepuryov [24]

Answer:

This is a triangular prism

Step-by-step explanation:

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3 years ago