We know that
x-------------> length rectangle launch tray
w------------< width rectangle launch tray------> 15 cm
<span>length is at least 20% greater than it's width
</span>x>=1.2w---------> x>=1.2*15
the answer part a) is
x>=18 ---------------> (<span> inequality to represent this situation)
part b) </span><span>suppose X is a whole number find the least possible permitted and the least possible area of the lunch tray
</span><span>
the least possible permitted length is 18 cm
</span>the least possible area of the lunch tray is 18*15=270 cm²
Answer:
:)
Step-by-step explanation:
to bad wow T^T
Answer:
i think the answer will be
{6} (11} {6,11}
but i'm not sure
a^2 + b^2 = c^2 pythagorean theorem
7^2 +24^2 = 25^2
49 + 576 = 25^2
625 = 25^2
25^2 =25^2
a^2 + b^2 = c^2 pythagorean theorem
9^2 + 40^2 = 41^2
81+1600 = 41^2
1681 = 41^2
41^2 = 41^2
