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3 years ago

Someone please help with this math question! ill give brainly if its correct

Mathematics

1 answer:

yanalaym [24]3 years ago

4 0

Answer:

x = 50, y = 61

Step-by-step explanation:

y + 8 + 2x + 11 = 180°

y + 2x = 161°

the total of the interior angles of the 5 sided polygon is:

(180 x 5) - 360 = 540°

540 = 98 + 98 + 125 + 108 + 2x + 11

2x = 100

x = 50°

y + 2(50) = 161

y = 61°

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Find the smallest number should be subtracted from 9340 so as to get a perfect square.

nikdorinn [45]

Square root of 9340 = 96.64

nearby number = 96

square of 96 = 9216

9340- 9216= 124

the smallest number 124 should be subtracted from 9340 so as to get a perfect square.

6 0

3 years ago

If an object is projected upward with an initial velocity of 126ft per? sec, its height h after t seconds is h=?16t^2+126t. Find

Archy [21]

Answer:

=760 ft

Step-by-step explanation:

h=16t^2+126t

Let t=4

h = 16 (4)^2 +126(4)

h = 16*16 +126(4)

=256+504

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5 0

4 years ago

Find x. Round your answer to the nearest tenth of a degree. Show your work.

ira [324]

Answer:

x = 63.7°

Step-by-step explanation:

Since the triangle is right we can use trig. ratios to solve

tan x° = $\frac{opposite}{adjacent}$ = $\frac{14.6}{7.2}$

⇒ x = $tan^{-1}$ ( $\frac{14.6}{7.2}$ ) = 63.7°

8 0

4 years ago

Can anyone do 4,5 and 6 for me plz

cricket20 [7]

For question 4, $sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.$

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

$sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.$

Step 2:

Using the above formula, we solve the following values

$sinA = \frac{oppositeside}{hypotenuse}$ $=\frac{a}{c}.$

$cosA = \frac{adjacentside}{hypotenuse}$ $= \frac{b}{c}.$

$tanB= \frac{opposite side}{adjacent side}$ $= \frac{b}{a}.$

$sinJ = \frac{oppositeside}{hypotenuse}$ $= \frac{j}{l}.$

$cosK = \frac{adjacentside}{hypotenuse}$ $= \frac{j}{l}.$

$tanK= \frac{opposite side}{adjacent side}$ $= \frac{k}{j}.$

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

$sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.$

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

$tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277$

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0

3 years ago

Identify the range of the function shown in the graph.

alukav5142 [94]

The range of a function is all possible y values that a function can take on.

In the case of the given function, the y values fluctuate between -1 and 1. Therefore, the range of the function is -1 <= y <= 1 (Option A).

Hope this helps!

3 0

2 years ago