Answer:
p=4x^3−3x^2+5x−2/x
Step-by-step explanation:
Let's solve for p.
px=4x^3−3x^2+5x−2
Step 1: Divide both sides by x.
px/x=4x^3−3x^2+5x−2/x
p=4x^3−3x^2+5x−2/x
Answer:
p=4x^3−3x^2+5x−2/x
( I hope this was helpful) >;D
<u>Answer </u><u>:</u>
In the given quadrilateral ABCD ,
- Angle BCA = 18°
- Angle ACD = 62°
Angle BCA = Angle CAD ( alternate interior angle )
Now in triangle CAD ,
We have two angles so by using angle sum property we can find the required third one ,
- Angle CAD + Angle ACD + Angle ADC = 180°
- 18 + 62 + Angle ADC = 180
- 80 + Angle ADC = 180
- Angle ADC = 180 - 80
- Angle ADC = 100
The answer is 0.5
Have an nice day!
Answer:
send the graph and ill solve it
Step-by-step explanation:
The first one is B
The second one is D
Hope this helps you!
