Question

X4+x3+7x2-6x+8 / x2+2x+8

Answer 1

Answer:

The Final answer will be $x^2-x+1$ with remainder 0.

Step-by-step explanation:

We have attached the division for your reference.

Given:

Dividend = $x^4+x^3+7x^2-6x+8$

Divisor = $x^2+2x+8$

Explaining the division we get;

Step 1: First when we divide the Dividend $x^4+x^3+7x^2-6x+8$ with divisor  $x^2+2x+8$ we will first multiply $x^2$ with the divisor then we get the Quotient as $x^2$  and Remainder as $-x^3-x^2-6x+8$

Step 2: Now the Dividend is $-x^3-x^2-6x+8$ and Divisor $x^2+2x+8$ is  we will now multiply $-x$ with the divisor then we get the Quotient as $x^2-x$ and Remainder as $x^2+2x+8$

Step 3: Now the Dividend is $x^2+2x+8$ and Divisor is $x^2+2x+8$ we will now multiply 1 with the divisor then we get the Quotient as $x^2-x+1$  and Remainder as 0.

Hence The Final answer will be $x^2-x+1$ with remainder 0.