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ratelena [41]
3 years ago
9

Describe a real-world object that would be measured using square units and another that would be measured using cubic units. Exp

lain.
Mathematics
1 answer:
Finger [1]3 years ago
4 0

Answer:

Volume or amount to f water in a jug

The size of a plot of land.

Step-by-step explanation:

The volume of capacity which a certain container can hold such as ; The amount water which can be filled into a cylindrical jug will be measured in cubic units as it requires the multiplication of 3 measured sides of the container ; for a cylinder, radius is squared and multiplied by height. (radius * radius * height).

The size or area of rectangular garden is measured using in square units as it only takes into consideration 2 of the measured parts of a shape.

You might be interested in
A triangle with the coordinates (6,4), (2,-1), and (-3,5) is translated 4 Units left and rotate 180 degrees about the origin. Wh
ankoles [38]

Answer:

(-2,-4),(2,1), and (7,-5)

Step-by-step explanation:

The given triangle has coordinates (6,4), (2,-1), and (-3,5).

When we translate 4 units left, the we obtain:

(6,4)------>(6-4,4)=(2,4)

(2,-1)----->(2-4,-1)=(-2,-1)

(-3,5)----->(-3-4,5)=(-7,5)

When the resulting figure is rotated 180° about the origin, the coordinates of the final figure becomes

(2,4)------>(-2,-4)

(-2,-1)----->(2,1)

(-7,5)------->(7,-5)

NB: The mapping for 180° rotation is:

(x,y)----->(-x,-y)

8 0
3 years ago
Given: Tangents LA and LB, m∠AOB=110°. Find: m∠ALO.
Yuri [45]

Answer:

The measure of angle ALO = 35°

Step-by-step explanation:

* Lets talk about the tangents to a circle drawn from a point

 outside the circle:

- They are equal in length

- They are perpendicular to the radii at the point of tang-ency

- If we join the points of tang-ency withe the center of the circle

 and join the outside point with center of the circle, we

 formed two congruent triangles

* Now lets check our problem

- AL and LB are two tangents to the circle O ant points A and B

∴ LA = LB ⇒ (1)

- OA and OB are radii in circle O

∴ OA = OB ⇒ (2)

∴ OA ⊥ AL and OB ⊥ BL ⇒ radius and tangent

∴ m∠OAL = 90° , m∠OBL = 90

∴ m∠OAL = m∠OBL ⇒ (3)

* From (1) , (2) , (3)

- The two triangles LAO and LBO are congruent ⇒ SAS

- SAS is one case of congruence

∵ The lengths of two sides and the measure of the including

  angle between them in one triangle equal to the

  corresponding sides and angles in the second triangle,

  then the two triangles are congruent

∴ m∠LOA = m∠LOB

∵ m∠AOB = 110°

∴ m∠LOA = m∠LOB = 110/2 = 55°

* In ΔLAO

∵ m∠ LAO = 90° , m∠LOA = 55°

∴ m∠ALO = 180 - (90 + 55) = 180 - 145 = 35°

* The measure of angle ALO = 35°

8 0
4 years ago
A data mining routine has been applied to a transaction dataset and has classified 88 records as fraudulent (30 correctly so) an
chubhunter [2.5K]

Answer:

The classification matrix is attached below

Part a

The classification error rate for the records those are truly fraudulent is 65.91%.

Part b

The classification error rate for records that are truly non-fraudulent is 96.64%

Step-by-step explanation:

The classification matrix is obtained as shown below:

The transaction dataset has 30 fraudulent correctly classified records out of 88 records, that is, 30 records are correctly predicted given that an instance is negative.

Also, there would be 88 - 30 = 58 non-fraudulent incorrectly classified records, that is, 58 records are incorrectly predicted given that an instance is positive.

The transaction dataset has 920 non-fraudulent correctly classified records out of 952 records, that is, 920 records are correctly predicted given that an instance is positive.

Also, there would be 952 - 920 = 32 fraudulent incorrectly classified records, that is, 32 records incorrectly predicted given that an instance is negative.

That is,

                                                                            Predicted value

                           Active value                 Fraudulent       Non-fraudulent

                              Fraudlent                         30                       58

                          non-fraudulent                   32                     920

The classification matrix is obtained by using the information related to the transaction data, which is classified into fraudulent records and non-fraudulent records.

The error rate is obtained as shown below:

The error rate is obtained by taking the ratio of \left( {b + c} \right)(b+c) and the total number of records.

The classification matrix is, shown above

The total number of records is, 30 + 58 + 32 + 920 = 1,040

The error rate is,

\begin{array}{c}\\{\rm{Error}}\,{\rm{rate}} = \frac{{b + c}}{{{\rm{Total}}}}\\\\ = \frac{{58 + 32}}{{1,040}}\\\\ = \frac{{90}}{{1,040}}\\\\ = 0.0865\\\end{array}  

The percentage is 0.0865 \times 100 = 8.65

(a)

The classification error rate for the records those are truly fraudulent is obtained by taking the rate ratio of b and \left( {a + b} \right)(a+b) .

The classification error rate for the records those are truly fraudulent is obtained as shown below:

The classification matrix is, shown above and in the attachment

The error rate for truly fraudulent is,

\begin{array}{c}\\FP = \frac{b}{{a + b}}\\\\ = \frac{{58}}{{30 + 58}}\\\\ = \frac{{58}}{{88}}\\\\ = 0.6591\\\end{array}  

The percentage is, 0.6591 \times 100 = 65.91

(b)

The classification error rate for records that are truly non-fraudulent is obtained by taking the ratio of d and \left( {c + d} \right)(c+d) .

The classification error rate for records that are truly non-fraudulent is obtained as shown below:

The classification matrix is, shown in the attachment

The error rate for truly non-fraudulent is,

\begin{array}{c}\\TP = \frac{d}{{c + d}}\\\\ = \frac{{920}}{{32 + 920}}\\\\ = \frac{{920}}{{952}}\\\\ = 0.9664\\\end{array}

The percentage is, 0.9664 \times 100 = 96.64

8 0
3 years ago
Jamal is baking 4 batches of chocolate chip cookies. He needs 2 13 cups of sugar for each batch. Which expression could be used
xz_007 [3.2K]

Answer:

8/13 cups of sugar

Step-by-step explanation:

Jamal is baking 4 batches of chocolate chip cookies. He needs 2 13 cups of sugar for each batch. Which expression could be used to determine the total amount of sugar that Jamal needs?

For the above question

1 batch of chocolate chips cookies = 2/13 cups of sugar

4 batches = x

Cross Multiply

x = 4 × 2/13 cups of sugar

x = 8/13 cups of sugar

7 0
3 years ago
Simplify this expression
Evgen [1.6K]

Answer:

2√65(13+√2)

=2√130+26√65 (Decimal: 232.42221)

Step-by-step explanation:

6 0
3 years ago
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