Simplify this expression

It is known that 10% of the 9-year old children in a town have three siblings. Fifteen 9-year old children are selected at rando

inn [45]

Using the binomial distribution, it is found that there is a 0.0555 = 5.55% probability that more than 3 of these selected children have three siblings.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem, for the parameters, we consider that:

10% of the 9-year old children in a town have three siblings, hence p = 0.1.

Fifteen 9-year old children are selected at random, hence n = 15.

The probability that more than 3 of these selected children have three siblings is given by:

$P(X > 3) = 1 - P(X \leq 3)$

In which:

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{15,0}.(0.1)^{0}.(0.9)^{15} = 0.2059$

$P(X = 1) = C_{15,1}.(0.1)^{1}.(0.9)^{14} = 0.3432$

$P(X = 2) = C_{15,2}.(0.1)^{2}.(0.9)^{13} = 0.2669$

$P(X = 3) = C_{15,3}.(0.1)^{3}.(0.9)^{12} = 0.1285$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.2059 + 0.3432 + 0.2669 + 0.1285 = 0.9445$

P(X > 3) = 1 - 0.9445 = 0.0555

0.0555 = 5.55% probability that more than 3 of these selected children have three siblings.

More can be learned about the binomial distribution at brainly.com/question/24863377

5 0

1 year ago

Six houses are located along the same road; the distances are shown. Where should the school bus stop to make the sum of distanc

sukhopar [10]

Hey there :)

Now lets name each house

A B C D E F
500ft <-> 500ft <-> 500ft <-> 500ft <-> 500ft <-> 2000ft

Let's say the bus stops at A
= 0 ( from A ) + 500 ( from B ) + 500 + 500 ( from C ) + 500 + 500 + 500 ( from D ) + 500 + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 500 + 2000 ( from F )
= 0 + 500 + 1000 + 1500 + 2000 + 4000
= 9000 ft

at B
= 500 ( from A ) + 0 ( from B ) + 500 ( from C ) + 500 + 500 ( from D ) + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 2000 ( from F )
= 500 + 0 + 500 + 1000 + 1500 + 3500
= 7000 ft

at C
= 500 ( from A ) + 500 + 500 ( from B ) + 0 ( from C ) + 500 ( from D ) + 500 + 500 ( from E ) + 500 + 500 + 2000 ( from F )
= 500 + 1000 + 0 + 500 + 1000 + 3000
= 6000 ft

Do the same for D , E and F

at D
= 6000 ft

at E
= 7000 ft

at F
= 15000 ft

You will find that the bus should stop at either C or D to make the sum of distances from every house to the stop as small as possible.

8 0

3 years ago

Read 2 more answers

How do u find the area of this figure

lorasvet [3.4K]

For the triangle use 14 for the height and 9 for the base. use the formula 1/2bh and multiple it by two.
for the circle do 3.14 times 9 squared and divided it by two. formula 3.14r^2.
the answer should be 317.34
hope this helps.

7 0

2 years ago

Multiply the following 11 x square Y and 2 x square y square

yaroslaw [1]

Answer:

$22 x^4y^3$