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3 years ago

4 times (12-8) + 2^3. (2 to the 3rd power)

Mathematics

1 answer:

brilliants [131]3 years ago

5 0

Answer:

It's 48. Heres why:

Step-by-step explanation:

Our equation, I believe, is 4[(12-8) + 2³]. We can do the operations in the parenthesis:

4[(4)+8] (12-8 = 4, and 2³ is 8). If we add 4 + 8, we get 12. Multiply 12 by 4, we get 48.

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what is the area of the shaded sector of the circle if the radius is 14 ft? leave your answer in terms of pi

Strike441 [17]

Given:

Radius = 14 ft

θ = 45°

To find:

Area of the shaded sector

Solution:

Area of the sector formula:

$$\text { area of sector }=\frac{\theta}{360^{\circ}} \times \pi r^{2}$

$$=\frac{45^\circ}{360^{\circ}} \times \pi \times 14^{2}$

$$=\frac{1}{8} \times \pi \times 196$

$=24.5\pi$ ft²

The area of the shaded sector of a circle is 24.5π ft².

3 0

4 years ago

Y^2 +5y+4= ???????????????

joja [24]

Answer:

y²+5y+4=y²+4y+y+4=y(y+4)+1(y+4)=

<u>(y+4)(y+1)</u>

4 0

3 years ago

In general, after a group makes a reservation at a restaurant, they do not show up 20% of the time. If a restaurant has 8 reserv

sashaice [31]

Answer:

P(more than 2 don't show up)=0.2031

Step-by-step explanation:

Multiplication rule for independent events:

If two events A and B are independent then the multiplication rule state that:

P(A and B)= P(A) x P(B)

Find the probability that more than two do not show up:

The probability that the reservations at the restaurant do not show up is 0.20 (=20%) and there were 8 reservations.

P(more than 2 don't show up)= 1- P(less than or equal to 2 don't show up)

= 1-( P(none show up) +P(one don't show up)+P(two don't show up)

=1- ((0.8⁸) +₈ C₁ (0.2¹)x(0.8⁷) +₈ C₂ (0.2²)x(0.8⁶)

=1- (0.1678 +0.3355+0.2936)= 1-0.7969

P(more than 2 don't show up)=0.2031

5 0

3 years ago

Help solve attached question.

LekaFEV [45]

Answer:

$\mathrm{12\sqrt{5} \: \: inches}$

Step-by-step explanation:

Use Pythagorean theorem, where:

$a^2+b^2=c^2$

Substitute in the values.

$24^2+12^2=c^2$

$c^2=576+144$

$c^2=720$

$c=\sqrt{720}$

$c=12\sqrt{5}$

$c=26.83281$

4 0

3 years ago

Read 2 more answers

Find (f −1)'(a).<br><br> f(x) = 4 + x2 + tan(πx/2), −1 < x < 1, a = 4

Vinvika [58]

Answer:

The solution is $(f^{-1})'(a) = \frac{2}{\pi }$

Step-by-step explanation:

From the question we are told that

The function is $f(x) = 4 + x^2 + tan [\frac{ \pi x}{2} ]$ , -1 < x < 1 a = 4

Here we are told find $(f^{-1}) (a)$

Let equate

$f(x) = a$

$4 + x^2 + tan[\frac{\pi x }{2} ] = 4$

$x^2 + tan[\frac{\pi x }{2} ] = 0$

For the equation above to be valid x must be equal to 0

Now when x = 0

$f(0) = 4+0^2 + tan [\frac{ \pi * 0}{2} ]$

=> $f(0) = 4$

=> $0 = f^{-1} (4)$

Differentiating f(x)

$f(x)' = 0 + 2x + sec^2 (\frac{\pi x}{2} )\cdot \frac{\pi}{2}$

Now

since $0 = f^{-1} (4)$

We have

$f(0)' = 0 + \frac{\pi }{2} sec^2 (0)$

$f(0)' = \frac{\pi }{2}$

Now

$(f^{-1})'(a) = \frac{1}{(\frac{\pi}{2} )}$

$(f^{-1})'(a) = \frac{2}{\pi }$

3 0

3 years ago