1 - 1/2c = 6
1 -1 - 1/2c = 6 -1 (subtract 1 on both sides)
-1/2c = 5 (next do the inverse operation)
c = 5 ÷ 1/2
c = -10
to check your answer substitute the value of c in the equation;
1- 1/2c = 6
1- 1/2(-10) = 6
1 + 5 = 6
6 =6
Answer:
x = 3 + √6 ; x = 3 - √6 ;
; 
Step-by-step explanation:
Relation given in the question:
(x² − 6x +3)(2x² − 4x − 7) = 0
Now,
for the above relation to be true the following condition must be followed:
Either (x² − 6x +3) = 0 ............(1)
or
(2x² − 4x − 7) = 0 ..........(2)
now considering the equation (1)
(x² − 6x +3) = 0
the roots can be found out as:

for the equation ax² + bx + c = 0
thus,
the roots are

or

or
and, x = 
or
and, x = 
or
x = 3 + √6 and x = 3 - √6
similarly for (2x² − 4x − 7) = 0.
we have
the roots are

or

or
and, x = 
or
and, x = 
or
and, x = 
or
and, 
Hence, the possible roots are
x = 3 + √6 ; x = 3 - √6 ;
; 
Answer:
1 1/5
Step-by-step explanation:
48/40 = 1 8/40
1 8/40 Simplify to 1 1/5
Hope this helps!
Answer:
Base ten blocks can represent values such as 1, 10, 100, and 1000.