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3 years ago

35.5 feet long 7.25 feet wide 7.5 feet tall approx volume of the tank

Mathematics

2 answers:

bulgar [2K]3 years ago

7 0

The answer is 1,930.3125

Mumz [18]3 years ago

3 0

wouldn't you multiply all three?

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Which is greater -2 or -2/3

Semmy [17]

Answer:

-2/3

Step-by-step explanation:

-2/3 is greater because it is closer to 0/positive than -2.

5 0

3 years ago

Write your answer in simplest radical form.

pantera1 [17]

9514 1404 393

Answer:

√3

Step-by-step explanation:

The ratio of the short sides to the hypotenuse in an isosceles right triangle is ...

1 : 1 : √2

This means ...

p·√2 = √6

p = (√6)/(√2) = √(6/2)

p = √3

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3 years ago

The ideal width of a certain conveyor belt for a manufacturing plant is 50 in. an actual conveyor belt can vary from the ideal b

Nastasia [14]

50 + 7/32 = 50 7/32
50 - 7/32 = 49 25/32

answers are :
c.) 49 25/32 < = x < = 50 7/32
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8 0

3 years ago

Bath and 1 yard of ribbon. She is 1/2 yard for project. She wants to divide the rest of the ribbon into pieces 1/4 yards long. H

ikadub [295]

Answer:

Step-by-step explanation:

Given:

Total length of ribbon = 1 yard

Length of ribbon used for project = $\frac{1}{2}$ yard

Length of ribbon the rest of ribbon is to be divided = $\frac{1}{4}$ yard

To find:

The number of ribbons of length $\frac{1}{4}$ yard that can be made = ?

Solution:

Length of ribbon left after the 1 yard ribbon is used for project can be calculated by subtracting the length of ribbon used from the initial length of ribbon.

i.e.

Length of ribbon left = $1-\frac{1}{2} =\frac{1}{2}$ yard

Now, number of ribbon of length $\frac{1}{4}$ yard can be found be dividing the length of ribbon left with the length of ribbon pieces to be cut.

i.e.

Number of ribbons:

$\dfrac{\frac{1}{2}}{\frac{1}{4}}\\\Rightarrow \dfrac{1}{2}\times 4 = 2$

3 0

3 years ago

How find derivative of function: y=arcsin(2x+1)<br> ...?

Setler [38]

$( \arcsin{x})'= \frac{1}{ \sqrt{1-x^2} } 
\\
\\ (\arcsin{(2x+1)})'= \frac{1}{ \sqrt{1-(2x+1)^2} } (2x+1)'= \frac{2}{ \sqrt{1-(4x^2+4x+1)} } =
\\
\\= \frac{2}{ \sqrt{-4x^2-4x} } =\frac{2}{ \sqrt{4x(-x-1} )} =\frac{2}{ 2\sqrt{x(-x-1} )} =\frac{1}{ \sqrt{x(-x-1} )}$

3 0

3 years ago