What is 60/50 as a percentage?
it would be 120
Probabilities are used to determine the chances of an event.
- The probability that the first contestant is a boy is 1/2
- The probability that the second contestant is a boy, if the first is a boy is 9/19
- The probabilities are not independent
The given parameters are:
<u>(a) Probability that first contestant is a boy</u>
This is calculated as:
This gives
<u>(b) Probability that the second contestant is a boy, if the first is a boy</u>
This is calculated as:
We subtracted 1, because the first contestant (a boy) is no longer part of the selection.
So, we have:
<u>(c) Independent probabilities</u>
The probabilities are not independent, because when a contestant is selected, the number of contestant is reduced by 1.
And this will affect the probability of the next selection.
Read more about probabilities at:
brainly.com/question/11234923
X^2 + 30x + 21
= ( x + 15)^2 - 225 + 21
= (x + 15)^2 - 204
Its D minimum at -204
The third one. The one that goes long box, short, short, long. That's because the first box isn't covered, and they next two are about half boxes showing and the last one is a full box again.
Expand the expression as
(<em>s</em> + 1)³/<em>s</em> ⁵ = (<em>s</em> ³ + 3<em>s</em> ² + 3<em>s</em> + 1)/<em>s</em> ⁵
… = 1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵
Then taking the inverse transform, you get
LT⁻¹ [1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵]
… = LT⁻¹ [1/<em>s</em> ²] + LT⁻¹ [3/<em>s</em> ³] + LT⁻¹ [3/<em>s</em> ⁴] + LT⁻¹ [1/<em>s</em> ⁵]
… = LT⁻¹ [1!/<em>s</em> ²] + 3/2 LT⁻¹ [2!/<em>s</em> ³] + 1/2 LT⁻¹ [3!/<em>s</em> ⁴] + 1/24 LT⁻¹ [4!/<em>s</em> ⁵]
… = <em>t</em> + 3/2 <em>t</em> ² + 1/2 <em>t</em> ³ + 1/24 <em>t</em> ⁴