D
is certainly wrong. You could extend the length of AD as far as you want and the two triangles (ABD and ACD) would still be congruent.
C
is wrong as well. The triangles might be similar, but they are more. They are congruent.
B
You don't have to prove that. It is given on the way the diagram is marked.
A
A is your answer. The two triangles are congruent by SAS
Answer:
Hence as long as x > 2/3, we can form a triangle from the three given sides.
Step-by-step explanation:
Given:
Length of 3 sides of triangle are 
Solution:
From the length of the 2nd side 4x, we know that x > 0
Let this be 1 st statement.
Now from the triangle inequality we can say that;

No new information from this because of the 1st statement above.
Also,

Lastly,

and again no new information is obtained from this inequality.
Hence as long as x > 2/3, we can form a triangle from the three given sides.
28 is the LCM of 4 and 7 as 4*7 = 28
Answer:
Domain: 3, 2, 1, 0, -1 , -2 , -3
Range: 5 , 4 , 3 , 2 , 1 , 0 , -1 , -2
Step-by-step explanation:
The domain values are all of the x-values, and the range value are all of the y-values. Domain ad range can also be know as input and output.
Answer:
V=a3
Step-by-step explanation: