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Natali [406]
3 years ago
9

Suppose that there is a coffee shop in an office(Which also has interns). It is observed that out of the people that visit the c

offee shop in a week 25% were female members, 40% were male members, 25% were female interns and 40% were male interns. These people are randomly asked about the coffee taste.
What is the probability that the first 6 people who are asked about the taste are all office members and not interns?
And what is the probability that the first intern that we talk to is a female?
Mathematics
1 answer:
ser-zykov [4K]3 years ago
8 0
The probability that the first 6 people who are asked that aren't interns is 35% 
The probability that the first intern that we talk to is a female is 25%
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Answer:

No does not contain the same length

Step-by-step explanation:

Given that

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Now

AB would be

= \sqrt{(1-(-4))^2 + (4-2)^2} \\\\= \sqrt{29}

And, BC is

= \sqrt{(2-1)^2 + 1-(-4))^2} \\\\= \sqrt{26}

As we can see that the AB and BC are not equaled

So,

AB ≠ BC

Due to the different length

Therefore they do not contains the same length

We simply applied the distance formula due to which the length could be determined and the same is to be considered

5 0
3 years ago
Which equation justifies why 9 1/3 = 3 square root of 9?
kozerog [31]

Answer: answer is A

Step-by-step explanation:

8 0
3 years ago
If the doctor’s office is 7 units from the zoo and 2 units from the park, which ordered pair could represent the location of the
s2008m [1.1K]

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Step-by-step explanation:

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Hope this helps :)

6 0
2 years ago
Read 2 more answers
tire and Jody's bedroom are shaped like rectangles Terrace bedroom is 9 ft long and 8 feet wide Jody's bedroom is 7 ft long and
zloy xaker [14]
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3 0
3 years ago
The following is a linear programming formulation of a labor planning problem. There are four overlapping shifts, and management
dexar [7]

Answer:

d. 15

Step-by-step explanation:

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13+12≥ 15

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At least 15 workers must be assigned to the shift 2.

The LP model questions require that the constraints are satisfied.

The constraint for the shift 2 is that the  number of workers must be equal or greater than 15

This can be solved using other constraint functions e.g

Putting  X4= 0 in

X1 + X4 ≥ 12

gives

X1 ≥ 12

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this does not satisfy the condition so this is wrong.

Now from

X2 + X3 ≥ 16

Putting X3= 14

X2 + 14 ≥ 16

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X2  ≥ 2

Putting these in the shift 2

X1 + X2 ≥ 15

13+2 ≥ 15

15 ≥ 15

Which gives the same result as above.

6 0
3 years ago
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