All categories

3 years ago

PLEASE HELP ASAP!!!!!

Mathematics

2 answers:

svet-max [94.6K]3 years ago

6 0

The answer to your question is x=31

Kitty [74]3 years ago

5 0

The total would be 180 degrees because angles on a straight line would always add up to 180.
(3x+31)+(2x-6)=180
5x+25=180
-25 -25
5x=155
/5 /5
x=31

You might be interested in

Simplify -1 – 8i —3— 51

ad-work [718]

Answer: 1=8i

Step-by-step explanation:

7 0

3 years ago

Let L be the line with parametric equations x=5+t,y=6,z=−2−3t. Find the vector equation for a line that passes through the point

scZoUnD [109]

Answer:

The required equations are

$(-5 \hat i + 7 \hat j + 8 \hat k )+\lambda \left((10+\frac {3}{\sqrt {10}})\hat i -\hat j +(6- \frac {9}{\sqrt {10}})\hat k\right)=0$ and

$(-5 \hat i + 7 \hat j + 8 \hat k )+\lambda \left((10-\frac {3}{\sqrt {10}})\hat i -\hat j +(6+ \frac {9}{\sqrt {10}})\hat k\right)=0$ .

Step-by-step explanation:

The given parametric equation of the line, $L$ , is $x=5+t, y=6, z=-2-3t,$ so, an arbitrary point on the line is $R(x,y,z)=R(5+t, 6, -2-3t)$

The vector equation of the line passing through the points $P(-5,7,-8)$ and $R(5+t, 6, -2-3t)$ is

$\vec P + \lambda \vec{(PR)}=0$

$\Rightarrow (-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((5+t-(-5))\hat i + (6-7)\hat j +(-2-3t-8)\hat k\right)=0$

$\Rightarrow (-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((10+t)\hat i -\hat j +(6-3t)\hat k\right)=0\;\cdots (i)$

The given equation can also be written as

$\frac {x-5}{1}=\frac {v-6}{0}=\frac{z+2}{-3}=t \; \cdots (ii)$

The standard equation of the line passes through the point $P_0(x_0,y_0,z_0)$ and having direction $\vec v= a_1 \hat i +a_2 \hat j +a_3 \hat k$ is

$\frac {x-x_0}{a_1}=\frac {y-y_0}{a_2}=\frac{z-z_0}{a_3}=t \;\cdots (iii)$

Here, The value of the parameter, $t$ , of any point $R$ at a distance $d$ from the point, $P_0$ , can be determined by

$|t \vec v|=d\;\cdots (iv)$

Comparing equations $(ii)$ and $(iii)$

The line is passing through the point $P_0 (5,6,-2)$ having direction $\vec v=\hat i -3 \hat k$ .

Note that the point $Q(5,6,-2)$ is the same as $P_0$ obtained above.

Now, the value of the parameter, $t$ , for point $R$ at distance $d=3$ from the point $Q(5,6,-2)$ can be determined by equation $(iv)$ , we have

$|t(\hat i -3 \hat k)|=3$

$\Rightarrow t^2|(\hat i -3 \hat k)|^2=9$

$\Rightarrow 10t^2=9$

$\Rightarrow t^2=\frac {9}{10}$

$\Rightarrow t=\pm \frac {3}{\sqrt {10}}$

Put the value of $t$ in equation $(i)$ , the required equations are as follows:

For $t= \frac {3}{\sqrt {10}}$

$(-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((10+\frac {3}{\sqrt {10}})\hat i -\hat j +\left(6-3\times \frac {3}{\sqrt {10}})\hat k\right)=0$

$\Rightarrow (-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((10+\frac {3}{\sqrt {10}})\hat i -\hat j +(6- \frac {9}{\sqrt {10}})\hat k\right)=0$

and for $t= -\frac {3}{\sqrt {10}}$ ,

$(-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((10+\left (-\frac {3}{\sqrt {10}}\right))\hat i -\hat j +(6-3\times \left(-\frac {3}{\sqrt {10}}\right)\hat k\right)=0$

$\Rightarrow (-5 \hat i + 7 \hat j - 8 \hat k )+\lambda \left((10-\frac {3}{\sqrt {10}})\hat i -\hat j +(6+ \frac {9}{\sqrt {10}})\hat k\right)=0$

8 0

3 years ago

Helpppppp giving brainliest

Fofino [41]

Answer:

6.25 lb and 100 oz

Step-by-step explanation:

One lb (Pound) is equal to 16 oz (Ounce). Therefore, 100 oz equals...

100 oz / 16 = 6.25 lb

and

100 oz = 100 oz

8 0

3 years ago

5x6 = (_X 6) + (2x_)

kati45 [8]

Answer:

(3 x 6) + (2 x 6)

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP MEE I CAN'T SOLVE THIS BY MYSELF!

UNO [17]

Answer:

x = 22

Step-by-step explanation:

The figure is attached below.

Its given that SV is parallel to RU. We have to find the value of x.

Observe that, if we join point V to U, we will obtain a parallelogram RSVU. One of the properties of a parallelogram is that the sum of its two adjacent angles is always 180 degrees.

So, the two adjacent angles would be: ∠S and ∠R

From the figure:

∠S = 5x + 4

∠R = 44 + x

Since,

∠S + ∠R must be 180 degrees, we can write:

∠S + ∠R = 180

5x + 4 + 44 + x = 180

6x + 48 = 180

6x = 132

x = 22

Therefore, the value of x is 22.

6 0

3 years ago