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bagirrra123 [75]
2 years ago
15

Someone please help?

Mathematics
1 answer:
3241004551 [841]2 years ago
7 0
I believe it is C but I’m not sure
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Which statement is true about the patterns in the two tables ?
MAXImum [283]

Answer: The fourth one

Step-by-step explanation:

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The Ford family decides they want to go see a movie at the local movie theater. The family consists of two adults, and five chil
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Ford Family consists of:

a) 2 adults

The price of ticket for each adult is $18.55. This can be approximated to $19 if we round it to nearest dollar. So the price of ticket for 2 adults will be 2 x 19 = $38

b) 3 children between ages 2 and 10.

Ticket for each child between ages 2 - 10 is $12.59 which can be approximated to $13. So ticket price for 3 children will be 3 x 13 = $39

c) 2 children below the age of 2.

Ticket price for each child is $6.54 which can approximated as $7. So ticket price for 2 children will be 2 x 7 = $14

The estimated total amount due on the family equals = 38 + 39 + 14 = $91

In each of the 3 cases we rounded up the values. So this means the actual amount must be slightly lesser than $91. The actual bill was $87.95 which is close to $91 and lesser than it. Hence we can conclude that $87.95 is the correct amount due for Ford Family.

3 0
3 years ago
Teachers are being trained to standardized the scores they give to students' essays. The same essay was scored by 10 different t
bagirrra123 [75]
What are you asking  , if you tell me i will solve
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3 years ago
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Last Tuesday was silly hat day at Toby's school. 74 students wore a silly hat and 666 students did not. What percentage of the s
valina [46]

Answer:

10%

Step-by-step explanation:

The total population of students will be equal to the sum of both those who wore the silly hat and those who didn't hence

Total students= 74+666=740

Number of students who wore silly hat is given as 74 hence when expressed as a percentage of the total students' population we get that

percentage of the students wore a silly hat=\frac {74\times 100}{740}=10\%

Therefore, 10% of students wore a silly hat last Tuesday

4 0
2 years ago
Fred has 30 minutes to do a three-problem quiz. He spent 10 7/10 minutes on question a and 5 2/5 minutes on question b. How much
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Answer:Fred has 13 9/10 minutes left for question C

Step-by-step explanation:

The total time that Fred has to do the three-problem quiz is 30 minutes.

He spent 10 7/10 minutes on question A. Converting 10 7/10 minutes to improper fraction, it becomes 107/10 minutes.

He spent 5 2/5 minutes on question B. Converting 5 2/5 minutes to improper fraction, it becomes 27/5 minutes.

Total time that Fred spent on question A and question B is

107/10 + 27/5 = (107 + 54)/10

= 161/10 minutes.

The amount of time that he has left for question C would be

30 - 161/10 = (300 - 161)/10 = 139/10

= 13 9/10 minutes

3 0
3 years ago
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