Find the distance between the points. Round to the nearest tenth if necessary. (4,3) |(1,-1)

-2(x-6)+7=35 How do I solve this equation with all the steps

vlada-n [284]

-2(x-6)+7=35 -2x+6+7=35 (Distributive property) -2x+13=35 (Simplify, combine like terms) -2x+13-13=35-13 -2x=22 -2x/-2=22/-2 X=-11

3 0

3 years ago

Yoshi multiplied -6.2 by -0.14. His result was -0.868. Which statement likely describes the error he made in his calculation?

Digiron [165]

Step-by-step explanation:

The answer is letter B. Negative and Negative is Positive.

3 0

3 years ago

What is the mode of the data set? a. 90 b. no mode c. 85.5 d. 49

grandymaker [24]

Answer:

90

Step-by-step explanation:

5 0

3 years ago

Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time t > 0 is $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

$\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t$

where, $\text{R}_i_n$ = concentration of salt in the inflow $\times$ input rate of brine solution

and $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

So, $\text{R}_i_n$ = 4 lb/gal $\times$ 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

= 3 gal/min - 2 gal/min

= 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, $\text{R}_o_u_t$ = concentration of salt in the outflow $\times$ outflow rate of brine solution

= $\frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min}$ = $\frac{2A(t)}{500+t} \text{ lb/min }$

Now, the differential equation for the amount of salt A(t) in the tank at a time t > 0 is given by;

= $\frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }$

or $\frac{dA}{dt}=12 - \frac{2A(t)}{500+t}$ .

4 0

3 years ago

A 7th grade teacher at a local middle school wants to know which

jekas [21]

The answer is Option C) 7th graders in her school.

In order to ascertain the suitability of a candidate for any popular position, his popularity can be assessed by taking a survey of the concerned sample.

7 0

2 years ago

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