Answer: 0.0035
Step-by-step explanation:
Given : The readings on thermometers are normally distributed with a mean of 0 degrees C and a standard deviation of 1.00 degrees C.
i.e.
and
Let x denotes the readings on thermometers.
Then, the probability that a randomly selected thermometer reads greater than 2.17 will be :_
![P(X>2.7)=1-P(\xleq2.7)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{2.7-0}{1})\\\\=1-P(z\leq2.7)\ \ [\because\ z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.9965\ \ [\text{By z-table}]\ \\\\=0.0035](https://tex.z-dn.net/?f=P%28X%3E2.7%29%3D1-P%28%5Cxleq2.7%29%5C%5C%5C%5C%3D1-P%28%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%5Cdfrac%7B2.7-0%7D%7B1%7D%29%5C%5C%5C%5C%3D1-P%28z%5Cleq2.7%29%5C%20%5C%20%5B%5Cbecause%5C%20z%3D%5Cdfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-0.9965%5C%20%5C%20%5B%5Ctext%7BBy%20z-table%7D%5D%5C%20%5C%5C%5C%5C%3D0.0035)
Hence, the probability that a randomly selected thermometer reads greater than 2.17 = 0.0035
The required region is attached below .
<u>To find the area of a complex shape</u>:
⇒ must split into simpler shapes
- a rectangle of <u>8m by 7m</u>
- a rectangle of <u>2m by 8 m</u>
<u>Now let's find</u>:
- Area of a rectangle of <u>8m by 7m</u>

- Area of a rectangle of <u>2m by 8m</u>

<u>Total Area</u> = 56 + 16 = <u>72 m²</u>
<u>Answer: 72 m²</u>
Hope that helps!
Is there a picture of it ? I need to see the picture
Cevap:
253
Adım adım açıklama:
23 ve 11'in çarpımı;
_____2 ___ 3
___ * _ 1 ____1
_________
_____2____3
_ + _ 2_3
____________
__2__5____3
____________
Dolayısıyla 23 * 11'in çarpımı 253'tür.
Hesap makinesi problemi çözmekte zorlanırsa aynı sonuç.
Answer:
B
Step-by-step explanation:
I believe that the answer to this question is B. I think this because I took 5.2 and divided it by 0.4 which gave me 13. I did 5.2 divided by 0.4 because it wanted to know how many times 0.4 goes into 5.2.
I hope this helps I am rlly srry if I am wrong. have a beautiful day.