2 years ago

The graph of y=x^2-4x is shown. name a zero of the function below

Mathematics

1 answer:

hoa [83]2 years ago

5 0

Answer:

0 and 4

Step-by-step explanation:

y = x^2 - 4x can be factored as follows: y = x(x - 4).

We find the zeros by setting this factored form equal to zero and solving for x:

x(x - 4) = 0, or x = 0, or x = 4.

The two zeros of this function are 0 and 4.

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3 years ago

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Answer:

18.7

Step-by-step explanation:

The Law of Cosines is $c^2=a^2+b^2-2ab cos(C)$ , where c is the unknown side length of a triangle, a and b are the remaining two side lengths, and C is the angle opposite to side c. To answer this question just plug in the known values:

$m^2=21^2+12^2-2(21)(12) cos(62)$

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$m^2=441+144-504 cos(62)$

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$m=\sqrt{585-504cos(62)}$

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3 years ago

Pleas help me with my question

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Answer:

Step-by-step explanation:

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