(X-5)2+3(X-5)+9 = 0
let expand the equation
(x)x2-(5)x2 + 3(x)-3(5) + 9 = 0
2x-10+3x-15+9=0
collect like terms
2x+3x-10-15+9 =0
5x-10-6 =0
5x-16=0
5x=0+16
5x=16
divide both side by 5 we have
x=16/5
Answer:
c
Step-by-step explanation:
Equations : Tiger Algebra gives you not only the answers, but also the complete step by step ... 5 x 2+5 x −5=0 ... 5x^2+5x-5=0 ... Parabola, Finding the Vertex: ... Root 2 at {x,y} = { 0.62, 0.00} ...
Use the Pythagoras' Theorem:
A^2 + B^2 = C^2
20^2 + 35^2 = C^2
400+ 1225=1625=C^2
square root of 1625= C = 40.31 km
