3 years ago

How do i write (n+5)(2n-3) in general form?

2 answers:

8 0

$(n+5)(2n-3) \\ \\ 2n^2 - 3n + 10n - 15 \\ \\ 2n^2 + (-3n + 10n) - 15 \\ \\ 2n^2 + 7n - 15 \\ \\$

The final result is: 2n<span>² + 7n - 15.</span>

Leona [35]3 years ago

8 0

(n - 5)(2n - 3)
n(2n - 3) - 5(2n - 3)
n(2n) - n(3) - 5(2n) + 5(3)
2n² - 3n - 10n + 15
2n² - 13n + 15

a₂ = 2
a₁ = -13
a₀ = 15

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