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Verdich [7]
3 years ago
12

How do i write (n+5)(2n-3) in general form?

Mathematics
2 answers:
Alexandra [31]3 years ago
8 0
(n+5)(2n-3) \\ \\ 2n^2 - 3n + 10n - 15 \\ \\ 2n^2 + (-3n + 10n) - 15 \\ \\ 2n^2 + 7n - 15 \\ \\

The final result is: 2n<span>² + 7n - 15.</span>
Leona [35]3 years ago
8 0
(n - 5)(2n - 3)
n(2n - 3) - 5(2n - 3)
n(2n) - n(3) - 5(2n) + 5(3)
2n² - 3n - 10n + 15
2n² - 13n + 15

a₂ = 2
a₁ = -13
a₀ = 15
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Answer:

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Step-by-step explanation:

Here, we want to determine the numerical length of JL

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Answer
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