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rusak2 [61]
2 years ago
13

Which ordered pair is a solution of the system of equations? y= 3x + 1 y= 5x - 1 A (2,3) © (1,2) B (0, 1) D (1,4)​

Mathematics
1 answer:
Vadim26 [7]2 years ago
7 0

Answer:

D

Step-by-step explanation:

So first, we have to test the pairs. Let start with equation 1.

7=\=3 x

4=\=2 x

0=0 ✓

4=4 ✓

Now we only have to test B and D.

0=\=-1

4=4 ✓

D is the correct answer.

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Barak spent $20 at the arcade. this represents 10%of the money earned by working at thepizza parlor last week.
Karolina [17]
20=10%
times 10
200=100%

he earned $200 at the parlor
4 0
3 years ago
If 5 times a number plus two is 17 what is the number​
sweet [91]

Answer:

3

Step-by-step explanation:

by question

5x+2=17

5×=15

×=3

8 0
3 years ago
Read 2 more answers
Help. IM SO LOST ON THIS! ;(
castortr0y [4]

Answer:

1. 4\frac{2}{3}

Step-by-step explanation:

For question 1, you need to know the ratio between the recipe and the amount in question.

So if in the recipe, it says it uses 3/4 cup of diced ham, and the question uses 1 cup of diced ham, you can divide 1 by 3/4 to get 4/3. This is how many times bigger the amount used in the question than the recipe.

Then it asks for how many cups of potatoes, to do this, you look at the recipe and how many potatoes it uses: 3.5 cups

To solve it then, you just do 3.5 x 4/3 to get 4\frac{2}{3} cups of potatoes

There's your answer.

3 0
3 years ago
A positive integer is 47 more than 9 times another. Their product is 1860. Find the two integers.
svlad2 [7]
X = 47 + 9y
xy = 1860

y(47 + 9y) = 1860
47y + 9y² = 1860
9y² + 47y - 1860 = 0

> using a quadratic equation solver on a calculator but you can also use the quadratic equation = [-b+/- √(b²-4ac)]/(2a)
> only integer solution is x = 12

12y = 1860
y = 155

integers are 12 and 155


8 0
3 years ago
A town has 5000 people in year t = 0. Calculate how long it takes for the population P to double once, twice, and three times, a
UNO [17]

Answer:

Step-by-step explanation:

At the time t = 0, population of the town = 5000

Rate of population increase = 500 per year

Therefore, the equation that will represent the population will be

P_{t}=P_{0}+500t

Where P_{t} = Population after t years

P_{0}= Initial population

t = Time in years

a). For double once the population will be 500×2 = 10000

By plugging in the values in the equation,

10000 = 5000 + 500t

500t = 10000 - 5000

500t = 5000

t = \frac{5000}{500}

t = 10 years

For Double twice,

Population will be = 10000×2 = 20000

Now we plug in the values in the equation again

20000 = 5000 + 500t

500t = 20000 - 5000

500t = 15000

t = \frac{15000}{500}

t = 30 years

For double thrice,

Population of the town = 20000×2 = 40000

Now we plug in the values in the equation,

40000 = 5000 + 500t

500t = 40000 - 5000

500t = 35000

t = \frac{35000}{500}

t = 70 years

b). If the population growth is 5%.

Then the growth will be exponential represented by

T_{n}=T_{0}(1+\frac{r}{100})^{t}

T_{n} = Population after t years

T_{0} = Initial population

t = time in years

For double once,

Population after t years = 10000

10000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{10000}{5000}

(1.05)^{t}=2

Take log on both the sides

log(1.05)^{t}=log2

tlog(1.05) = log2

t = \frac{log2}{log1.05}

t = 14.20 years

For double twice,

Population after t years = 20000

20000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{20000}{5000}

(1.05)^{t}=4

Take log on both the sides

log(1.05)^{t}=log4

tlog(1.05) = log4

t = \frac{log4}{log1.05}

t = 28.413 years

For double thrice

Population after t years = 40000

40000=5000(1+\frac{5}{100})^{t}

(1.05)^{t}=\frac{40000}{5000}

(1.05)^{t}=8

Take log on both the sides

log(1.05)^{t}=log8

tlog(1.05) = log8

t = \frac{log8}{log1.05}

t = 42.620 years

4 0
2 years ago
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