Ask question

Ask question

All categories

Ad libitum [116K]

3 years ago

11

.Lakewood Auditorium For the next movement, the director tells the students to move on the stage so that rectangle ZYXW is trans

lated 25 feet to the left and 20 feet down. What are the coordinates of rectangle Z′Y′X′W′ '?

1 answer:

bekas [8.4K]3 years ago

5 0

Answer:

hwhjwjaikwkww jajjksisiofee oakw

You might be interested in

What segment is congruent to DE. FD,AC,AB,BC

Dahasolnce [82]

Your answer is AB. Congruent is when two sides or a shape are equal.

8 0

3 years ago

Read 2 more answers

If y = ax² + bx + c is the general form of a quadratic function, what is y = a(x - h)² + k? *

Ierofanga [76]

Step-by-step explanation:

it is the vertex form.

remember, (h, k) is the vertex point.

the vertex being the point of the (quadratic) parabola, where the curve turns around.

depending on the orientation of the parabola (vertex up or vertex down) as defined by the sign of a, this is either the minimum or the maximum of the curve.

so, the first a. is correct.

and so is the second a., as they play an important role when completing the square and hence finishing the transformation.

3 0

3 years ago

if the coefficient of determination for a data set is 0.25 and the SSE for the data set is 24, what is the SST for the data set?

NeTakaya

The answer is 32 on apex

7 0

4 years ago

Read 2 more answers

2(x+3)^(2)+8=0 Solve.

olga2289 [7]

Answer:

2i-3

Step-by-step explanation:

2(x+3)²=-8

(x+3)²=-4

x+3=2i

x=2i-3

7 0

3 years ago

A potential energy function is given by U = A x3 + B x2 − C x + D . For positive parameters A, B, C, D this potential has two eq

Ivenika [448]

Answer:

7.8655

Step-by-step explanation:

Given the functionl

$U=Ax^3+Bx^2-cx+D$

Where,

$A=1.45J/m^3\\B=2.85J/m^2\\c= 1.7J/m\\D=0.6J$

We have, replacing,

$U=1.45x^3+2.85x^2-1.7x+0.6$

We need to derivate and verify for stable equilibrum that,

$\frac{d^2 U}{dx^2}>0$

Then,

$U'(x) = 4.32x^2+5.7x-1.7$

Roots in,

$x_1=-1.57008\\x_2=0.250636$

We obtain U"(x), then we have

$\frac{d^2U}{dx}=8.64x+5.7$

For $x=-1.57, U"(x)=-7.86549$ Unestable

For $x=0.250636 U"(x)=7.8655>0$ Stable

7 0

3 years ago