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kenny6666 [7]
3 years ago
6

. According to a recent report, people smile an average of µ = 62 times per day. Assuming that the distribution of smiles is app

roximately normal with a standard deviation of σ = 18, find each of the following values: a. What proportion of people smile more than 80 times a day
Mathematics
1 answer:
Leokris [45]3 years ago
6 0
Idk my horse face sorry dear
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Bryan is observing the velocity of a cyclist at different times. After four hours, the velocity of the cyclist is 15 km/h. After
Gnoma [55]
The best way to solve this problem is to graph all variables, velocity being the dependent variable (y-axis) and time being the independent variable (x-axis) . Since we are given two points for the two variables, we use the point-slope formula to get the slope which happens to be -1. We then use the standard form y = mx + b and substitute m with -1. Next we want to find b, we will again use the point slope formula now knowing m to be -1. we chose point 0 for time(x-axis) and at zero, we obtain a value of your b which happens to be +19. A line graph would better visualize my point. Cheers!
 
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3 years ago
What is the value of in e^4?
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7 0
4 years ago
Read 2 more answers
PLEASE HELP AND SHOW WORK!!
Nastasia [14]

Answer:

Pipe 1 alone fills a tank in 10 min

Pipe 2 alone fills the tank in 20 min

If both are turned on together, how long will it take to fill the tank???

Pipe 1 fills at the RATE of 1/10th tank per min

Pipe 2 fills at the RATE of 1/20th tank per min

Pipe 1 + Pipe 2 fills at the rate of 1/10+1/20 or 3/20th tank per min

Let x= time to fill the tank

(3/20)(x)=1 Where 1 denotes a full tank (Multiply both sides by 20)

3x=20

x=6 2/3 min----------both working together

NOW YOUR PROBLEM

Let x= amount of time for smaller pipe to fill the tank

Then (x-5)=amount of time for larger pipe to fill the tank

NOW HERE'S WHERE THE RECIPROCAL COMES IN:

The smaller pipe fills the tank at the RATE of 1/x cu units per min

The larger tank fills the tank at the RATE of 1/(x-5) cu units per min

Together, they fill the tank at the rate of 1/x+(1/(x-5)) cu units per min

But now we are told that together the fill the tank in 11 1/9 minutes. so our equation to solve is:

(1/x+(1/(x-5))(11 1/9)=1 where 1 denotes a full tank. In fact, in each of the above reciprocals, the 1 denotes a full tank.

So, dividing both sides by 11 1/9, we get:

1/x+(1/(x-5)=1/(11 1/9)-------------- which is your equation

I assume that you have no problems solviing this eq.

Hope this helps----ptaylor

Step-by-step explanation:

7 0
3 years ago
PLEASEE HELP!
melamori03 [73]

Answer:

Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.

Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity

Step-by-step explanation:

Given that the vector b = (-2, -1) can be written as follows;

b = -2·i - j, we have;

\left | b \right | = √((-2)² + (-1)²) = √5

Therefore, we have;

The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)

Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2

The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))

Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.

7 0
3 years ago
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