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timurjin [86]
2 years ago
13

IS THIS IN SIMPLIST FORM? PLEASE HELP! TY! 2( x - 3 + 2 )

Mathematics
1 answer:
Phoenix [80]2 years ago
3 0

Answer:

2x - 2

Step-by-step explanation:

There are two steps to take here.  First add together the -3 + 2 in the brackets:

2(x - 3 + 2)

= 2(x - 1)

Now use the distributive property and multiply each term in the brackets by two:

2(x - 1)

= 2x - 2

And you now have it in simplest form.

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Which term has the definition "A portion of the population"?
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Answer:

A.

Step-by-step explanation:

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2 years ago
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How do you divide 400 by 10 to the power of 3
Ivanshal [37]
10 to the power of 3 is 1000, and 400 divided by 1000 is 0.4 because you move the decimal place over 3 in the number 400 to get 0.4.
8 0
3 years ago
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Solve for b.<br> r = (b-5)m
alukav5142 [94]

Answer:

b=5m+r/m

Step-by-step explanation:

Let's solve for b.

r=(b−5)(m)

Step 1: Flip the equation.

bm−5m=r

Step 2: Add 5m to both sides.

bm−5m+5m=r+5m

bm=5m+r

Step 3: Divide both sides by m.

bm/m=5m+r/m

b=5m+r/m

Answer:

b=5m+r/m

6 0
3 years ago
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find the area of triangle qpm. round the answer to the nearest tenth. a. 5.2 square units b. 6.3 square units c. 6.5 square unit
viva [34]
Pls. see attachment. 

We need to solve for the angles of the smaller triangle in order to solve for the angle of the larger triangle which would help us solve the missing measurement of a side.

Given:

51 degrees.

Cut the triangle into two equal sides and it forms a right triangle. All interior angles of a triangle sums up to 180 degrees.

180 – 51 – 90 = 39 degrees

39 degrees * 2 = 78 degrees.

Angle Q is 78 degrees.

In the bigger triangle, 4.3 is the hypotenuse. We need to solve for the measurement of the long leg which is the opposite of the 78 degree angle.

We will use the formula:

Sine theta = opposite / hypotenuse

Sin(78 deg) = opposite / 4.3

Sin(78 deg) * 4.3 = opposite

4.21 = opposite. This is also the height of the triangle.

 

Area of a triangle = ½ * base * height

A = ½ * 3units * 4.21units

A = 6.315 square units.

7 0
3 years ago
Find all points on the portion of the plane x+y+z=5 in the first octant at which f(x, y, z) = xy2z2 has a maximum value.
irina1246 [14]
Lagrange multipliers:

L(x,y,z,\lambda)=xy^2z^2+\lambda(x+y+z-5)

L_x=y^2z^2+\lambda=0
L_y=2xyz^2+\lambda=0
L_z=2xy^2z+\lambda=0
L_\lambda=x+y+z-5=0

\lambda=-y^2z^2=-2xyz^2=-2xy^2z

-y^2z^2=-2xyz^2\implies y=2x (if y,z\neq0)

-y^2z^2=-2xy^2z\implies z=2x (if y,z\neq0)

-2xyz^2=-2xy^2z\implies z=y (if x,y,z\neq0)

In the first octant, we assume x,y,z>0, so we can ignore the caveats above. Now,

x+y+z=5\iff x+2x+2x=5x=5\implies x=1\implies y=z=2

so that the only critical point in the region of interest is (1, 2, 2), for which we get a maximum value of f(1,2,2)=16.

We also need to check the boundary of the region, i.e. the intersection of x+y+z=5 with the three coordinate axes. But in each case, we would end up setting at least one of the variables to 0, which would force f(x,y,z)=0, so the point we found is the only extremum.
4 0
3 years ago
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