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olchik [2.2K]
3 years ago
10

Use the functions a(x) = 3x + 10 and b(x) = 5x − 6 to complete the function operations listed below.

Mathematics
2 answers:
Romashka-Z-Leto [24]3 years ago
8 0

Answer:

(a + b) = 8x +4

(a - b) = -2x +16

(a * b) = 15x^{2}+32x-60

Step-by-step explanation:

We have been given the functions;

a(x) = 3x + 10 and b(x) = 5x − 6

Part A:

(a + b) = a(x) + b(x) # we simply add the two given functions

(a + b) = 3x + 10 + 5x − 6

(a + b) = 8x + 4

Part B:

(a - b) = a(x) - b(x) # we simply subtract the two given functions

(a - b) = (3x + 10 ) - (5x − 6)

(a - b) = 3x + 10 -5x +6

(a - b) = -2x + 16

Part C:

(a * b) = a(x)*b(x)

# we simply find the product of the two given functions

(a * b) = (3x + 10)*(5x − 6)

(a * b) = 15x^{2}-18x+50x-60=15x^{2}+32x-60

Masja [62]3 years ago
4 0

Part A

The functions a(x) = 3x + 10 and b(x) = 5x − 6 to complete the function operations listed below.

(a+b)(x)=a(x)+b(x)

(a+b)(x)=(3x+10)+(5x-6)

(a+b)(x)=3x+5x+10-6

(a+b)(x)=8x+4

Part B.

(a-b)(x)=a(x)-b(x)

(a-b)(x)=(3x+10)-(5x-6)

Expand the parenthesis to get:

(a-b)(x)=3x+10-5x+6

(a-b)(x)=3x-5x+10+6

(a-b)(x)=-2x+16

Part C

(a*b)(x)=a(x)*b(x)

(a*b)(x)=(3x+10)*(5x-6)

We expand to get:

a \times b = 15 {x}^{2} - 18x + 50x - 60

a \times b = 15 {x}^{2}  + 32x - 60

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Next, we should subtract 7 from both sides to cancel out the 7 on the right side.
-16 = 2t
Finally, we should divide both sides by 2.
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Now let's move on to the next equation.

b) 4(5x-2) = 7(2x+3)
Let's use the distributive property to get rid of the parentheses and their coefficients.
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Now, lets subtract 14x from both sides of the equation.

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Next, let's add 8 to both sides of the equation.

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And divide both sides by the coefficient of x, which is 6.

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