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Zigmanuir [339]
2 years ago
13

Solve the system by substitution.....

Mathematics
2 answers:
kow [346]2 years ago
8 0

Answer:

x=-2

y=-20

Step-by-step explanation:

y=10x

y=2x-16

10x=2x-16

-2x -2x

8x=-16

/8 /8

x=-2

y=10x

y=10(-2)

y=-20

bazaltina [42]2 years ago
5 0

Answer: y=-20,:x=-2

PLEASE MARK BRAINLIEST

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− 4 /5 + 40/75 +100%
Reika [66]

Answer:

0.266666666

Step-by-step explanation:

7 0
2 years ago
Complete the function table below function<br> f(x) = 6x -3
taurus [48]
When x is equal to -1:
f(-1)=6(-1)-3
=-7-3
=-10
y=-10

When x is equal to 0:
f(0)=6(0)-3
=0-3
=-3
y=-3

When x is equal to 1:
f(1)=6(1)-3
=6-3
=3
y=3

When x is equal to 2:
f(2)=6(2)-3
=12-3
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y=9
6 0
3 years ago
Write an equation showing the relationship between the number of baskets (b) made from outside the three-point line and the numb
Scorpion4ik [409]
P=3b

p is the total number of points scored. Since there are 3 points being scored, you multiply that by the number of baskets made, b.
4 0
2 years ago
Read 2 more answers
Help me please and thanks
Arturiano [62]

This is the answer its easy just simplify the inequality

3 0
3 years ago
Question A volleyball team sold raffle tickets to raise money for the upcoming season. They sold three different types of ticket
m_a_m_a [10]

Answer:

24 premium tickets were sold.

Step-by-step explanation:

Let :

Deluxe ticket = x

Regular tickets = x + 78

Premium tickets = y

x + (x + 78) + y = 208

4x + 2(x+78) + 10y = 714

2x + y = 208 - 78

4x + 2x + 156 + 10y = 714

2x + y = 130 - - - - - (1)

6x + 10y = 558 - - - - (2)

Now we can solve the simultaneous equation using elimination method :

From (1)

y = 130 - 2x

Put y = 130 - 2x in (2)

6x + 10(130 - 2x) = 558

6x + 1300 - 20x = 558

- 14x = 558 - 1300

-14x = - 742

x = 742 / 14

x = 53

Put x = 53 in y = 130 - 2x

y = 130 - 2(53)

y = 130 - 106

y = 24

3 0
2 years ago
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