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3 years ago

A bag of candy contains 400 pieces of which 40% are red. How many pieces are red?

Mathematics

1 answer:

xz_007 [3.2K]3 years ago

6 0

Answer:

Step-by-step explanation:

40% of 400 = 0.40×400 = 160

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22 POINTS

Harlamova29_29 [7]

Answer:

C. 2, -2, -6

Step-by-step explanation:

18, 14, 10, 6, ?

18 - 4 = 14

14 - 4 = 10

10 - 4 = 6

6 - 4 = 2

2 - 4 = -2

-2 - 4 = -6

They are subtracting each number by 4 to get the next one that continues.

Hope this helped!

Have a supercalifraglisticexpialidocious day!

7 0

3 years ago

Read 2 more answers

Write and equation with aa variable on both sides of the equal sign that has infinitely many solutions. solve the equation and e

LekaFEV [45]

X = x

to solve, subtract both sides by x:

0 = 0

x is always equals to x so infinite solutions

8 0

4 years ago

Please help me I really need help I’m gonna give 33 points for this please help

lidiya [134]

Answer:

Step-by-step explanation:

1a) use letter "P" for perimeter

1b) use letter "L" or "x"

1c) Formula: P=4L or P=4x

2) the formula for the perimeter of a square is P=4L or P=4x because to find the perimeter you have to add up all the sides, and for a square, all the sides are equal, so it is P=4L or P=4x.

4 0

4 years ago

Read 2 more answers

Find the least common multiple (LCM) of 8y^6+ 144y^5+ 640y^4 and 2y^4 + 40y^3 + 200y^2.

Mice21 [21]

Answer:

LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

Step-by-step explanation:

Making factors of $8y^{6}+ 144y^{5}+ 640y^{4}$

Taking $8y^{4}$ common:

$\Rightarrow 8y^{4} (y^{2}+ 18y+ 80)$

Using factorization method:

$\Rightarrow 8y^{4} (y^{2}+ 10y + 8y + 80)\\\Rightarrow 8y^{4} (y (y+ 10) + 8(y + 10))\\\Rightarrow 8y^{4} (y+ 10)(y + 8))\\\Rightarrow \underline{2y^{2}} \times 4y^{2} \underline{(y+ 10)}(y + 8)) ..... (1)$

Now, Making factors of $2y^{4} + 40y^{3} + 200y^{2}$

Taking $2y^{2}$ common:

$\Rightarrow 2y^{2} (y^{2}+ 20y+ 100)$

Using factorization method:

$\Rightarrow 2y^{2} (y^{2}+ 10y+ 10y+ 100)\\\Rightarrow 2y^{2} (y (y+ 10) + 10(y + 10))\\\Rightarrow \underline {2y^{2} (y+ 10)}(y + 10) ............ (2)$

The underlined parts show the Highest Common Factor(HCF).

i.e. HCF is $2y^{2} (y+ 10)$ .

We know the relation between LCM, HCF of the two numbers 'p' , 'q' and the numbers themselves as:

$HCF \times LCM = p \times q$

Using equations (1) and (2): $\Rightarrow 2y^{2} (y+ 10) \times LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times 2y^{2} (y+ 10)(y + 10)\\\Rightarrow LCM = 2y^{2} \times 4y^{2}(y+ 10)(y + 8) \times (y + 10)\\\Rightarrow LCM = 8y^{4}(y+ 10)^{2}(y + 8)$

Hence, LCM = $8y^{4}(y+ 10)^{2}(y + 8)$

5 0

3 years ago

a minor league baseball team plays 114 games in a season. if the team won 14 more than three times as many games as they lost, h

Rainbow [258]

They will have played with 19 loses 76 wins !

7 0

3 years ago