Find the median, first quartile, third quartile, and interquartile range of the data.

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Ulleksa [173]

As the world I’m heading towards and matching up to is getting bigger

It makes me feel an emptiness somehow

What part it is, even if the shape is maybe like this

Even when myself can’t come to know it

As if solving up the scattered pieces

We are matching up our stories

Inside the empty spot in my heart, there’s a piece called you taking place

I just know it at first glance I saw you

You’re my missing puzzle piece

Finally I solved it

You filled every piece of my heart, even the scarred part of it to the fullest

And somehow, you’ve become my everything

My missing puzzle piece

The fact that I have a flaw,

The truth that I am imperfect All of it makes me feel small

But in between those gaps

We can fill one another with it

So I don’t even realized that it was empty

“Hello, it’s been so long, isn’t it?”

The small piece that I put in my pocket and carry around everywhere

Please be with me so it can be fuller and prettier

After I met you, I’m able to draw a bigger picture

You’re my missing puzzle piece

Finally I solved it

You filled every piece of my heart, even the scarred part of it to the fullest

And somehow, you’ve become my everything

My missing puzzle piece

More than having everything, Not losing that one thing is more important

Through you, I came to know that

You’re my missing puzzle piece

Very dazzling

It becomes one scene inside the world that I’ve been trying to put together alone

Like the hands that are interlocking tight together,

Because without you, it can’t be completed

So that we won’t lose each other,

My missing puzzle piece

4 0

3 years ago

Read 2 more answers

Please help

In-s [12.5K]

Answer:

2y + 12

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Hey plz help i’ve been stuck

BARSIC [14]

Answer:

Um, I just see a black square! Maybe could you try reuploading a picture?

Step-by-step explanation:

5 0

3 years ago

A manufacturer of widgets wants to test a new widget-producing machine to determine if it can make an average of 25 widgets per

klio [65]

Using the t-distribution, it is found that since the p-value is greater than 0.01, there is no evidence that the new machine should be rejected at the 0.01 significance level.

<h3>What are the hypothesis tested?</h3>

At the null hypothesis, it is tested if the average is not less than 25, that is:

$H_0: \mu \geq 25$

At the alternative hypothesis, it is tested if the average is less than 25, that is:

$H_1: \mu < 25$

<h3>What is the test statistic?</h3>

The test statistic is given by:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

s is the standard deviation of the sample.

n is the sample size.

Considering the situation described, the values of the parameters are given as follows:

$\overline{x} = 24.97, \mu = 25, s = 2.16, n = 10$

Hence the test statistic is:

$t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{24.97 - 25}{\frac{2.16}{\sqrt{10}}}$

t = -0.04

<h3>What is the p-value and the conclusion?</h3>

Using a t-distribution calculator, for a left-tailed test, as we are testing if the mean is less than a value, with 10 - 1 = 9 df and t = -0.04, the p-value is of 0.4844.

Since the p-value is greater than 0.01, there is no evidence that the new machine should be rejected at the 0.01 significance level.

More can be learned about the t-distribution at brainly.com/question/13873630

#SPJ1

3 0

2 years ago

Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The

sattari [20]

Answer:

C. H0 : p = 0.8 H 1 : p ≠ 0.8

The test is:_____.

c. two-tailed

The test statistic is:______p ± z (base alpha by 2) $\sqrt{\frac{pq}{n} }$

The p-value is:_____. 0.09887

Based on this we:_____.

B. Reject the null hypothesis.

Step-by-step explanation:

We formulate null and alternative hypotheses as proportion of people who own cats is significantly different than 80%.

H0 : p = 0.8 H 1 : p ≠ 0.8

The alternative hypothesis H1 is that the 80% of the proportion is different and null hypothesis is , it is same.

For a two tailed test for significance level = 0.2 we have critical value ± 1.28.

We have alpha equal to 0.2 for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28

The test statistic is

p ± z (base alpha by 2) $\sqrt{\frac{pq}{n} }$

Where p = 0.8 , q = 1-p= 1-0.8= 0.2

n= 200

Putting the values

0.8 ± 1.28 $\sqrt{\frac{0.8*0.2}{200} }$

0.8 ± 0.03620

0.8362, 0.7638

As the calculated value of z lies within the critical region we reject the null hypothesis.

8 0

3 years ago