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kolbaska11 [484]
1 year ago
14

Which of these is an exponential parent function? OA. f(x)=2x-2 OB. f(x) = 2x C. f(x) = 2x + 3 OD. f(x) = 24x​

Mathematics
1 answer:
melomori [17]1 year ago
5 0

The answer to this question is choice B

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if the farm needs to pack 12,70,224 litchis in boxes that hold 144 litchis ,how many boxes would be required .​
uysha [10]

For this, we will divide 1,270,224 by 144.

1,270,224 ÷ 144 = 8,821.

For this result, we can conclude that the number of boxes required to pack 1,270,224 litchis is 8,821 boxes.

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What is the value of x?<br><br><br><br> Enter your answer in the box.
hoa [83]
The answer is x = 9, hope this helps- mark brainliest if you can please thanks
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write an inequality that represents the phrase the sum of 1 and y is greater than or equal to 3 .Check to see if y =1 is a soult
Volgvan
1+y≥3
1+1≥3 is not true so y=1 is not a solution.

Hope this helps:)<span />
8 0
3 years ago
(1)/(31)x^(2)-25=0 <br> a) {+5}<br> b) {+30}<br> c) {+6/5}<br> d) {+5/6}
ahrayia [7]

Answer:

B

Step-by-step explanation:

Please Mark me brainly

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7 0
3 years ago
Pls help asap whats the local min value of the function below?
shutvik [7]

Answer:

<em>given function has 2 minimums</em> - \frac{9}{4}  and  \frac{9}{4}  

Step-by-step explanation:

<u><em>Step 1.</em></u> g'(x) = 4x³ - 10x

<u><em>Step 2.</em></u> Find find the critical points:

4x³ - 10x = 2x(2x² - 5) = 0

x_{1} = - \sqrt{\frac{5}{2} } , x_{2} = 0 , x_{3} = \sqrt{\frac{5}{2} }

<u><em>Step 3.</em></u> g'(x) > 0 :  - \sqrt{\frac{5}{2} } < x < 0  or  x > \sqrt{\frac{5}{2} }

g'(x) < 0 :   x < - \sqrt{\frac{5}{2} }   or   0 < x < \sqrt{\frac{5}{2} }

<u><em>Step 4.</em></u>

If x ∈ ( - ∞ , - \sqrt{\frac{5}{2} } ) , g(x) is decreasing ;

If x = - \sqrt{\frac{5}{2} } , g(x) has <em>minimum</em> value ;

If x ∈ ( - \sqrt{\frac{5}{2} } , 0 ) , g(x) is increasing ;

If x = 0 , g(x) has maximum value ;

If x ∈ ( 0 , \sqrt{\frac{5}{2} } ) , g(x) is decreasing ;

If x = \sqrt{\frac{5}{2} } , g(x) has <em>minimum</em> value ;

If x ∈ ( \sqrt{\frac{5}{2} } , ∞ ) , g(x) is increasing .

⇒ at ( - \sqrt{\frac{5}{2} } , - \frac{9}{4} ) and at ( \sqrt{\frac{5}{2} } , \frac{9}{4} ) , g(x) reaches its minimum

8 0
3 years ago
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