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3 years ago

Simplify. Please help.

Mathematics

2 answers:

Agata [3.3K]3 years ago

4 0

Answer:

4^8

Step-by-step explanation:

When multiplying powers, keep the base the same and add the exponents.

4^6 x 4^2 = 4^8

NemiM [27]3 years ago

3 0

Answer:

I believe it is B

Step-by-step explanation:

if correct pls mark brainliest

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Pete estimates that he has spent $64.50 on supplies for his lawn mower. He charges $12 per lawn for his service. Write a linear

nadya68 [22]

Answer:

The equation representing the Amount of profit Peter earns is $y=12x-64.5$ .

Step-by-step explanation:

Given:

Money spent on supplies = $64.50

Per lawn charge for mowing lawn = $12

Solution:

Let the amount of profit Pete earns be represented by 'y'.

Let the number of lawns to be mowed be represented by 'x'

Now we can say that:

Amount of profit Pete earns is equal to Per lawn charge for mowing lawn multiplied by number of lawns to be mowed minus Money spent on supplies.

framing in equation form we get;

$y=12x-64.5$

Hence The equation representing the Amount of profit Peter earns is $y=12x-64.5$ .

7 0

4 years ago

4. Parking fees at IIUM are RM 5.00 for IIUM students and RM 7.50 for non-IIUM students. At the

professor190 [17]

Answer:

(a) 780 students and 960 non-students

(b) No. The maximum revenue is RM9000 from 1200 non-students.

(c). Revenue is maximum of RM9000 at 1200 non-students, decreasing by RM2.50 per student to a minimum of RM6000 at 1200 students

Step-by-step explanation:

Let x = IIUM students and

and y = non-IIUM students

You have two conditions

(a) x + y = total vehicles parked

(b) 5.00x + 7.50y = total gross receipts

(a) Wednesday

From your table,

x + y = 1740

5.00x + 7.70y = RM11 100

Solve the simultaneous equations

$\begin{array}{rrcrl}(1) & x + y & = &1740&\\(2) & 5.00x + 7.50y & = & 11 100\\(3)& 5.00x + 5.00y & = & 8700 & \text{Multiplied (1) by 5}\\&2.50 y & = &2400 &\text{Subtracted (3) from (2)}\\(4)&y& = &\mathbf{960} &\text{Divided each side by 2.50}\\& x +960& = &1740& \text{Substituted (4) into (1)}\\& x& = &\mathbf{780}& \\\end{array}\\\text{There are $\large \boxed{\textbf{780 students and 960 non-students}}$}$