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Phantasy [73]
2 years ago
10

Which number line represents the solution of 4x - 9 > - 21?

Mathematics
1 answer:
Aleks04 [339]2 years ago
3 0

Answer:4x -9 >= -21

4x >= -12

x >= -12/4

x >= -3  

so this number line started with -3 and go away till + infinity  

hope this will help you

You might be interested in
Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
3 years ago
The product of two numbers is 10 times the value of 8 × 7. Which expression shows the two numbers?
Aleonysh [2.5K]

Answer: 7 x 80 i think


Step-by-step explanation:\

nothing


8 0
2 years ago
Can someone help me please? Am I right or no?
Juliette [100K]
The figure consists of three objects, a rectangle, a trapezoid, a triangle

Find the area of the rectangle
The rectangle is 16 in long and 9 in wide
a₁ = l × w
a₁ = 16 × 9
a₁ = 144 in²

Find the area of the trapezoid
The base of trapezoid is 31 in and 16 in, and the height is 35 - 20 = 15 in.
a₂ = 1/2 × (a + b) × h
a₂ = 1/2 × (31 + 16) × 15
a₂ = 1/2 × 47 × 15
a₂ = 352.5 in²

Find the area of the triangle
The base of the triangle is 31 in, the height is 20 in
a₃ = 1/2 × b × h
a₃ = 1/2 × 31 × 20
a₃ = 310 in²

Add the area together
a = a₁ + a₂ + a₃
a = 144 + 352.5 + 310
a = 806.5

The answer is 806.5 in²
4 0
2 years ago
Someone please help me will give BRAILIEST!!!!!!
Misha Larkins [42]
The answer would be 1/5
8 0
3 years ago
I need help seeing what I did wrong
Makovka662 [10]

Answer:  The two roots are x = 3/2 and x = -2

=========================================================

Explanation:

You have the right idea so far. But the two numbers should be 3 and -4 since

  • 3*(-4) = -12
  • 3+(-4) = -1

The -1 being the coefficient of the x term.

This means you need to change the -3x and 4x to 3x and -4x respectively. The other inner boxes are correct.

---------

Refer to the diagram below to see one way to fill out the box method, and that helps determine the factorization.

If we place a 2x to the left of -2x^2, then we need an -x up top because 2x*(-x) = -2x^2

Then based on that outer 2x, we need a -2 up top over the -4x. That way we get 2x*(-2) = -4x

So we have the factor -x-2 along the top

The last thing missing is the -3 to the left of 3x. Note how -3*(-x) = 3x in the left corner and -3*(-2) = 6 in the lower right corner.

We have the factor 2x-3 along the left side.

---------

The two factors are (2x-3) and (-x-2) which leads to the factorization (x+3)(-x+2)

The last thing to do is set each factor equal to 0 and solve for x

  • 2x-3 = 0 solves to x = 3/2 = 1.5
  • -x-2 = 0 solves to x = -2

The two roots are x = 3/2 and x = -2

8 0
3 years ago
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